Linux Cron：每 1 秒运行一次 cron？
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Cron: running cron every 1 second?
提问by Crazy_Bash
How can I run cron every 1 second? there's only minutes option by default
如何每 1 秒运行一次 cron？默认情况下只有分钟选项
采纳答案by Pete Wilson
Let cron start the job one time, the first time. Put the program in an infinite loop, sleep() for 1 second at the end of each loop. like this, in C:
让 cron 开始工作一次，第一次。将程序置于无限循环中，在每个循环结束时 sleep() 1 秒钟。像这样，在 C 中：
int main( int argc, char ** argv ) {
while (1) {
// do the work
sleep(1000);
}
}
Could that work?
那能行吗？
回答by Marc B
You can't with cron, because 1 minute is THEminimum time interval available. You'd have to run a script that fires up 60 other scripts, with delays of 0 to 59 seconds, or a single script which re-runs itself 60 times.
你不能用cron的，因为1分钟时的最小时间间隔可用。您必须运行一个脚本来启动 60 个其他脚本，延迟为 0 到 59 秒，或者一个脚本可以重新运行 60 次。
But at that point, why not just run a single script outside of cron which does sleep(1) in a loop?
但是在这一点上，为什么不只在 cron 之外运行一个脚本来循环执行 sleep(1) 呢？
回答by UtahJarhead
Cron executes stuff every minute. Use a script:
Cron 每分钟执行一次。使用脚本：
while :
do
sleep 1
some_command || break
done
or in one line:
或在一行中：
while : ; do sleep 1 ; some_command || break ; done
This will wait 1 second in between each execution, so if your command takes .75 seconds to run, then this script will kick it off every 1.75 seconds.
这将在每次执行之间等待 1 秒，因此如果您的命令需要 0.75 秒来运行，那么此脚本将每 1.75 秒启动一次。
