如何在 Spring 中绑定属性的字符串数组？
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How to bind a string array of properties in Spring?
提问by SebS
I have the following in my application.properties file
我的 application.properties 文件中有以下内容
some.server.url[0]=http://url
some.server.url[1]=http://otherUrl
How do I refer to the array of properties using the @Value anotation inside a @Bean method?
如何在 @Bean 方法中使用 @Value 注释来引用属性数组？
I am using Java 6 with Tomcat 7 and Spring boot 1.4
我在 Tomcat 7 和 Spring boot 1.4 中使用 Java 6
采纳答案by user3567935
Follow these steps
按着这些次序
1) @Value("${some.server.url}") private List urls;
1) @Value("${some.server.url}") 私有列表网址；
2) @ConfigurationProperties("some.server") public class SomeConfiguration {
2) @ConfigurationProperties("some.server") public class SomeConfiguration {
3) You should have getter and setter for instance variable 'urls'
3）你应该有getter和setter实例变量'urls'
回答by Aman Tuladhar
I was also having the same problem as you mentioned and it seems using index form on application.propertieswas not working for me either.
我也遇到了与您提到的相同的问题，似乎使用索引表单对application.properties我也不起作用。
To solve the problem I did something like below
为了解决这个问题，我做了类似下面的事情
some.server.url = url1, url2
Then to get the those properties I simply use @Value
然后为了获得我简单使用的那些属性 @Value
@Value("${some.server.url}")
private String[] urls ;
Springautomatically splitsthe String with commaand return you an Array. AFAIKthis was introduced in Spring 4+
Spring自动用逗号分割String并返回一个Array。这是在AFAIKSpring 4+
If you don't want comma (,)as seperator you have to use SpELlike below.
如果您不想comma (,)作为分隔符，则必须使用如下所示的SpEL。
@Value("#{'${some.server.url}'.split(',')}")
private List<String> urls;
where split()accepts the seperator
wheresplit()接受分隔符
回答by Shawn Clark
You can use a collection.
您可以使用集合。
@Value("${some.server.url}")
private List<String> urls;
You can also use a configuration class and inject the bean into your other class:
您还可以使用配置类并将 bean 注入其他类：
@Component
@ConfigurationProperties("some.server")
public class SomeConfiguration {
private List<String> url;
public List<String> getUrl() {
return url;
}
public void setUrl(List<String> url) {
this.url = url;
}
}
