jQuery 如何使用jquery获取css样式的值
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how to get the value of css style using jquery
提问by iMarkDesigns
I'd like to know what type of method should I use to get the value of CSS style. I want to set it to jQuery so that I can create conditions to match on CSS "left" value.
我想知道我应该使用什么类型的方法来获取 CSS 样式的值。我想将它设置为 jQuery,以便我可以创建条件来匹配 CSS“左”值。
Here is the CSS and HTML tag with the style attributes.
这是带有样式属性的 CSS 和 HTML 标签。
<div class="items" style="left: -900px"> <span>some content here</span> </div>
Here is my jQuery code to get the value.
这是我获取值的 jQuery 代码。
<script>
var n = $("items").css("left");
if(n == -900){
$(".items span").fadeOut("slow");
}
</script>
I'd like to know if this method is correct because it is not working in my end. Thanks in advance for the little help.
我想知道这种方法是否正确,因为它最终不起作用。在此先感谢您的帮助。
Note: left value was dynamic, and it was changing to these value: -900px, -1800px, -2700px, -3600px, -4500px...
注意:左值是动态的,它正在更改为以下值:-900px、-1800px、-2700px、-3600px、-4500px...
回答by ?????
I doubt css understands left
by itself. You need to use it specifying position. You are using .css() correctly
我怀疑 cssleft
自己理解。您需要使用它来指定位置。您正在正确使用 .css()
position: relative/absolute/whatever;
left: 900px;
heres a fiddle of it working
继承人的小提琴工作
and without the position here's what you get
没有这个职位,这就是你得到的
Change your if statement to be like this - with quotes around -900px
将您的 if 语句更改为这样 - 周围有引号 -900px
var n = $("items").css("left");
if(n == '-900px'){
$(".items span").fadeOut("slow");
}
回答by Hammad Khan
You code is correct. replace items with .items as below
你的代码是正确的。用 .items 替换 items 如下
<script>
var n = $(".items").css("left");
if(n == -900){
$(".items span").fadeOut("slow");
}
</script>
回答by Skatox
Yes, you're right. With the css()
method you can retrieve the desired css value stored in the DOM. You can read more about this at: http://api.jquery.com/css/
你是对的。使用该css()
方法,您可以检索存储在 DOM 中的所需 css 值。您可以在以下位置阅读更多相关信息:http: //api.jquery.com/css/
But if you want to get its position you can check offset()and position()methods to get it's position.
但是如果你想得到它的位置,你可以检查offset()和position()方法来获取它的位置。