Java 想要一个用于验证印度车辆编号格式的正则表达式？
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/6386300/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Want a regex for validating Indian Vehicle Number Format?
提问by Asif
Hello everyone here...
大家好，这里...
I need to build up a swing application related to vehicle registration and in which i want to do input the vehicle number of indian standard, like:
我需要建立一个与车辆登记相关的摇摆应用程序，我想在其中输入印度标准的车辆编号，例如：
MP 09 AB 1234
AH 17 FT 2387
UT 32 DR 6423
DL 01 C AA 1111
MP 09 AB 1234
AH 17 英尺 2387
UT 32 DR 6423
DL 01 C AA 1111
More Specifically,
进一步来说，
Please if any one can help me?
DocumentFiltertype class can also help me.........
请如果有人可以帮助我吗？
DocumentFiltertype 类也可以帮我.........
采纳答案by Alix Axel
Based on the Wikipedia spec:
基于维基百科规范：
^[A-Z]{2}[ -][0-9]{1,2}(?: [A-Z])?(?: [A-Z]*)? [0-9]{4}$
- The first two letters of the registration plate represent the State in which the vehicle is Registered.
- The next two digit numbers are the sequential number of a district. Due to heavy volume of vehicle registration, the numbers were given to the RTO offices of registration as well.
- The third part is a 4 digit number unique to each plate. A letter(s) is prefixed when the 4 digit number runs out and then two letters and so on.
- In some states (such as the union territory of Delhi, and the state of Gujarat) the initial 0 of the district code is omitted; thus Delhi district 2 numbers appear as DL 2 not DL 02.
- The National Capital Territory of Delhi has an additional code in the registration code: DL 01 C AA 1111
- 车牌的前两个字母代表车辆注册所在的州。
- 接下来的两位数字是一个区的序号。由于车辆登记量很大，这些号码也提供给 RTO 登记处。
- 第三部分是每个板唯一的 4 位数字。一个或多个字母在 4 位数字用完时加上前缀，然后是两个字母，依此类推。
- 在某些州（例如德里的联邦领土和古吉拉特邦），地区代码的首字母 0 被省略；因此，德里 2 区号码显示为 DL 2 而不是 DL 02。
- 德里国家首都辖区在注册码中多了一个代码：DL 01 C AA 1111
回答by MoarCodePlz
Try this
尝试这个
^[A-Z]{2}\s[0-9]{2}\s[A-Z]{2}\s[0-9]{4}$
^means start of string [A-Z]{2}means 2 characters in the range of A through Z\smeans white space[0-9]{2}means 2 characters in the range of 0 through 9\smeans white space[A-Z]{2}means 2 characters in the range of A through Z\smeans white space[0-9]{4}means 4 characters in the range of 0 through 9$means end of string
^表示字符串的开头[A-Z]{2}表示 A 到 Z 范围内的 2 个字符\s表示空白[0-9]{2}表示 0 到 9 范围内的2 个字符\s表示空白[A-Z]{2}表示 A 到 Z 范围内的 2 个字符\s表示空白[0-9]{4}表示范围内的 4 个字符0 到 9$表示字符串结束
Based on what you said in your question this should be a very broad check against proper format, but I have a feeling that there are more specific regulations on how the license plates are numbered. Let me know if there are additional constraints for the regex.
根据您在问题中所说的内容，这应该是对正确格式的非常广泛的检查，但我觉得对于车牌的编号方式有更具体的规定。让我知道正则表达式是否有其他限制。
回答by K6t
just check it out for whitespace only...
只需检查一下是否有空格...
function isValidNumber($Number){
$pattern = "^[a-zA-z]{2}\s[0-9]{2}\s[0-9]{4}$";
if (eregi($pattern, $Number)){
return true;
}
else {
return false;
}
}
回答by Fredrik Pihl
^[A-Z]{2} [0-9]{2} [A-Z]{2} [0-9]{4}$
See http://en.wikipedia.org/wiki/Vehicle_registration_plates_of_India
见http://en.wikipedia.org/wiki/Vehicle_registration_plates_of_India
Looks like the format is a bit more complex than stated in your question...
看起来格式比您的问题中陈述的要复杂一些......
回答by Asif
Say for example if the user already entered a value like:
例如，如果用户已经输入了一个值，例如：
DL
then the textbox did not take the next input any other than a integer or one more char as.....
然后文本框没有将下一个输入作为整数或多一个字符作为......
DL C
from here user can only enter a integer value............
从这里用户只能输入一个整数值........
So, in short what i want to do is to take the input only like that regex given by Alix
所以，简而言之，我想要做的就是只像 Alix 给出的正则表达式一样接受输入
Based on the Wikipedia Specs
基于维基百科规范
^[A-Z]{2}[ -][0-9]{1,2}(?: [A-Z])?(?: [A-Z]*)? [0-9]{4}$
回答by Sachin Daingade
-(BOOL) validateVehicleRegNumber:(NSString *)strNumber { //Example MH14DA8904
-(BOOL) validateVehicleRegNumber:(NSString *)strNumber { //示例 MH14DA8904
NSString *validReg = @"[A-Z]{2}[0-9]{2}[A-Z]{2}[0-9]{4}";
NSPredicate *emailTest = [NSPredicate predicateWithFormat:@"SELF MATCHES %@", validReg];
return [emailTest evaluateWithObject:strNumber];
}
}
回答by Ketan sangle
^[A-Z]{2}\s[0-9]{1,2}\s[A-Z]{1,2}\s[0-9]{1,4}$
The above regex will work for the following types
上述正则表达式适用于以下类型
DL 01 AA 1111
DL 01 AA 1111
DL 0 AA 1111
DL 0 AA 1111
DL 1 A 1111
DL 1 A 1111
DL 0 A 11
DL 0 A 11
DL 01 AA 111
DL 01 AA 111
回答by Manoj Chavanke
//DL 01 C AA 1234
^[A-Z]{2}[ -]{0,1}[0-9]{2}[ -]{0,1}(?:[A-Z])[ -]{0,1}[A-Z]{1,2}[ -]{0,1}[0-9]{1,4}$
//MH 15 AA 1234
^[A-Z]{2}[ -]{0,1}[0-9]{2}[ -]{0,1}[A-Z]{1,2}[ -]{0,1}[0-9]{1,4}$
MVA 1234
^[A-Z]{3}[ -]{0,1}[0-9]{1,4}$
//MH 15 8008
^[A-Z]{2}[ -]{0,1}[0-9]{2}[ -]{0,1}[0-9]{1,4}$
with or without space :)
有或没有空间:)
回答by ked
If you are looking for number plate in substring then use the following regex
如果您要在子字符串中查找车牌号，请使用以下正则表达式
.*?([A-Za-z]{2})(\d{2})([A-Za-z]{2})(\d{4}).*?
