Laravel 框架中的继承
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Inheritance in Laravel framework
提问by Belsen
Is possibile to use inheritance in laravel model? I explain:
是否可以在 Laravel 模型中使用继承？我解释：
is possible to exend a model, which extends eloquent class?
是否可以扩展一个模型，它扩展了 eloquent 类？
class A extends Eloquent
{
}
class B extends A
{
}
A e B are also 2 different tables and B has A_id as foreignkey and other fields. How could be the constructor of class B? is it a ragionable solution or better use hasOne relationship?
A e B 也是 2 个不同的表，B 有 A_id 作为外键和其他字段。B类的构造函数怎么可能？这是一个合理的解决方案还是更好地使用 hasOne 关系？
no every A object are also B object. Es. user and teacher
不是每个 A 对象也是 B 对象。埃斯。用户和教师
Thank you
谢谢
回答by Martin Bean
I'm having difficulty understanding your supplementary details, but in answer to the actual question: yes, it is possible to extend Eloquent models.
我很难理解您的补充细节，但在回答实际问题时：是的，可以扩展 Eloquent 模型。
<?php
class User extends \Eloquent {
protected $table = 'users';
}
class Student extends User {
protected $table = 'students';
}
Be warned though, that any methods (such as relations, scopes etc) willpropagate to the extending class. If this is not desired, then create a base class that has the minimum of what you need, and then sub-class it with your specific types, i.e. Student, Administratoretc.
但是请注意，任何方法（例如关系、范围等）都将传播到扩展类。如果这不是您想要的，那么创建一个具有您需要的最少数量的基类，然后使用您的特定类型对其进行子类化，即Student，Administrator等等。
Another approach is to use interfaces. So if you knowmodels need the same attributes but will say, have different relations; then you can create an interface to add those constraints:
另一种方法是使用接口。因此，如果您知道模型需要相同的属性，但会说具有不同的关系；然后您可以创建一个接口来添加这些约束：
<?php
interface UserInterface {
public function getName();
}
class User extends \Eloquent implements UserInterface {
protected $table = 'users';
public function getName()
{
return $this->name;
}
}
class Student extends \Eloquent implements UserInterface {
protected $table = 'students';
public function getName()
{
return $this->name;
}
public function courses()
{
return $this->belongsToMany('Course');
}
public function grades()
{
return $this->hasMany('Grade');
}
}
回答by Belsen
I resolve with
我解决了
class A extends Eloquent
{
protected $table = 'a';
}
class B extends A
{
protected $table = 'b';
protected $primaryKey = 'a_id';
}
but in the main function:
但在主函数中：
$f = B::find(1);$f->method();
$f = B::find(1);$f->method();
where the method() is a method of A class,
the system gives to me an mysql error:
其中method()是A类的方法，系统给我一个mysql错误：
select * fromCwhereC.B_id= 1
the error is B_id. It should be A_id cause the method shold be applied from subobject of the class, not from the class
select * fromC whereC .B_id= 1
错误是 B_id。它应该是 A_id 因为该方法应该从类的子对象中应用，而不是从类中应用
