PHP 获取当前目录的名称
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PHP Get name of current directory
提问by Satch3000
I have a php page inside a folder on my website.
我的网站上的文件夹中有一个 php 页面。
I need to add the name of the current directory into a variable for example:
我需要将当前目录的名称添加到变量中，例如：
$myVar = current_directory_name;
Is this possible?
这可能吗？
回答by Andreas Wong
getcwd();
or
或者
dirname(__FILE__);
or (PHP5)
或 (PHP5)
basename(__DIR__)
http://php.net/manual/en/function.getcwd.php
http://php.net/manual/en/function.getcwd.php
http://php.net/manual/en/function.dirname.php
http://php.net/manual/en/function.dirname.php
You can use basename()to get the trailing part of the path :)
您可以使用basename()来获取路径的尾随部分:)
In your case, I'd say you are most likely looking to use getcwd(), dirname(__FILE__)is more useful when you have a file that needs to include another library and is included in another library.
在您的情况下，我会说您最有可能希望使用getcwd(),dirname(__FILE__)当您的文件需要包含另一个库并且包含在另一个库中时更有用。
Eg:
例如：
main.php
libs/common.php
libs/images/editor.php
In your common.phpyou need to use functions in editor.php, so you use
在您common.php需要在 中使用函数editor.php，因此您使用
common.php:
common.php：
require_once dirname(__FILE__) . '/images/editor.php';
main.php:
main.php：
require_once libs/common.php
That way when common.php is require'din main.php, the call of require_oncein common.phpwill correctly includes editor.phpin images/editor.phpinstead of trying to look in current directory where main.phpis run.
这样，当的common.php是require'd在main.php，的通话require_once中common.php会包含正确editor.php的images/editor.php，而不是试图在当前目录下查找其中main.php运行。
回答by yesnik
To get only the name of the directory where script executed:
仅获取执行脚本的目录的名称：
//Path to script: /data/html/cars/index.php
echo basename(dirname(__FILE__)); //"cars"
回答by user2169219
For EXAMPLE
例如
Your Path = /home/serverID_name/www/your_route_Dir/
Your Path = /home/serverID_name/www/your_route_Dir/
THIS_is_the_DIR_I_Want
THIS_is_the_DIR_I_Want
A Soultion that WORKS:
一个有效的灵魂：
$url = dirname(\__FILE__);
$array = explode('\\',$url);
$count = count($array);
echo $array[$count-1];
回答by Ameer Ul Islam
echo basename(__DIR__); will return the current directory name only
echo basename(__FILE__); will return the current file name only
回答by Andrew
Actually I found the best solution is the following:
其实我发现最好的解决方案如下：
$cur_dir = explode('\', getcwd());
echo $cur_dir[count($cur_dir)-1];
if your dir is www\var\path\ Current_Path
如果你的目录是 www\var\path\ Current_Path
then this returns Current_path
那么这将返回Current_path
回答by MK2009
$myVar = str_replace('/', '', $_SERVER[REQUEST_URI]);
$myVar = str_replace('/', '', $_SERVER[REQUEST_URI]);
libs/images/index.php
Result: images
libs/图像/index.php
结果：图像
回答by Dziamid Harbatsevich
If you have PATH and do not want to make concern if your script works in the folder you are interested in then this work out:
如果你有 PATH 并且不想担心你的脚本是否在你感兴趣的文件夹中工作，那么这个工作：
basename(parse_url($_GET['dir_link'])['path'],PHP_URL_PATH)
