javascript 循环遍历未知数量的数组参数

Looping through unknown number of array arguments

提问by swaggyP

I am trying to figure out how to loop through several array arguments passed. For example: [1,2,3,4,5],[3,4,5],[5,6,7] If I pass it to a function, how would I have a function loop inside each argument (any number of arrays can be passed) ?

我想弄清楚如何遍历传递的几个数组参数。例如：[1,2,3,4,5],[3,4,5],[5,6,7] 如果我将它传递给一个函数，我将如何在每个参数（任何可以传递多少个数组）？

I want to use a for loop here.

我想在这里使用 for 循环。

回答by James McLaughlin

You can use argumentsfor this:

您可以为此使用参数：

for(var arg = 0; arg < arguments.length; ++ arg)
{
    var arr = arguments[arg];

    for(var i = 0; i < arr.length; ++ i)
    {
         var element = arr[i];

         /* ... */
    } 
}

回答by Banoona

Use forEach, as below:

使用 forEach，如下：

'use strict';

    function doSomething(p1, p2) {
        var args = Array.prototype.slice.call(arguments);
        args.forEach(function(element) {
            console.log(element);
        }, this);
    }

    doSomething(1);
    doSomething(1, 2);

回答by Darren

Use the built in argumentskeyword which will contain the lengthof how many arrays you have. Use that as a basis to loop through each array.

使用内置arguments关键字，它将包含length您拥有的数组数量。以此为基础循环遍历每个数组。

回答by David

function loopThroughArguments(){
    // It is always good to declare things at the top of a function, 
    // to quicken the lookup!
    var i = 0,
        len = arguments.length;

    // Notice that the for statement is missing the initialization.
    // The initialization is already defined, 
    // so no need to keep defining for each iteration.
    for( ; i < len; i += 1 ){

        // now you can perform operations on each argument,
        // including checking for the arguments type,
        // and even loop through arguments[i] if it's an array!
        // In this particular case, each argument is logged in the console.
        console.log( arguments[i] );
    }

};