C语言 如何存储然后打印二维字符/字符串数组？
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how to store and then print a 2d character/string array?
提问by guitar_geek
Suppose I have the words: tiger, lion, giraffe.
假设我有这些词：老虎、狮子、长颈鹿。
How can I store it in a two dimensional chararray using forloop and scanfand then print the words one by one using a forloop?
如何char使用for循环将其存储在二维数组中scanf，然后使用循环一个一个地打印单词for？
Something like
就像是
for(i=0;i<W;i++)
{
scanf("%s",str[i][0]); //to input the string
}
PS Sorry for asking such a basic question, but I couldn't find a suitable answer on Google.
PS 很抱歉问这么基本的问题，但我在谷歌上找不到合适的答案。
回答by Ran Eldan
First you need to create an array of strings.
首先，您需要创建一个字符串数组。
char arrayOfWords[NUMBER_OF_WORDS][MAX_SIZE_OF_WORD];
Then, you need to enter the string into the array
然后，您需要将字符串输入到数组中
int i;
for (i=0; i<NUMBER_OF_WORDS; i++) {
scanf ("%s" , arrayOfWords[i]);
}
Finally in oreder to print them use
最后为了打印它们使用
for (i=0; i<NUMBER_OF_WORDS; i++) {
printf ("%s" , arrayOfWords[i]);
}
回答by Magn3s1um
char * str[NumberOfWords];
str[0] = malloc(sizeof(char) * lengthOfWord + 1); //Add 1 for null byte;
memcpy(str[0], "myliteral#include<stdio.h>
#include<malloc.h>
int main()
{
char *str[3];
int i;
int num;
for(i=0;i<3;i++)
{
printf("\n No of charecters in the word : ");
scanf("%d",&num);
str[i]=(char *)malloc((num+1)*sizeof(char));
scanf("%s",str[i]);
}
for(i=0;i<3;i++) //to print the same
{
printf("\n %s",str[i]);
}
}
");
//Initialize more;
for(int i = 0; i < NumberOfWords; i++){
scanf("%s", str[i]);
}
回答by Santhosh Pai
You can do this way.
你可以这样做。
1)Create an array of character pointers.
1）创建一个字符指针数组。
2)Allocate the memory dynamically.
2）动态分配内存。
3)Get the data through scanf. A simple implementation is below
3）通过scanf获取数据。一个简单的实现如下
#include<stdio.h>
int main()
{
char str[6][10] ;
int i , j ;
for(i = 0 ; i < 6 ; i++)
{
// Given the str length should be less than 10
// to also store the null terminator
scanf("%s",str[i]) ;
}
printf("\n") ;
for(i = 0 ; i < 6 ; i++)
{
printf("%s",str[i]) ;
printf("\n") ;
}
return 0 ;
}
