相当于 Bash 中的 __FILE__ 和 __LINE__
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Equivalent of __FILE__ and __LINE__ in Bash
提问by user368507
Is there any variable in bash that contains the name of the .sh file executed? The line number would be great too.
bash 中是否有任何变量包含执行的 .sh 文件的名称？行号也会很棒。
I want to use it in error messages such as:
我想在错误消息中使用它，例如：
echo "ERROR: [$FILE:L$LINE] $somefile not found"
采纳答案by ezpz
#!/bin/bash
echo $LINENO
echo `basename #!/bin/bash
MY_NAME=`basename $ cat xx
#!/bin/bash
_ERR_HDR_FMT="%.23s %s[%s]: "
_ERR_MSG_FMT="${_ERR_HDR_FMT}%s\n"
error_msg() {
printf "$_ERR_MSG_FMT" $(date +%F.%T.%N) ${BASH_SOURCE[1]##*/} ${BASH_LINENO[0]} "${@}"
}
error_msg "here"
error_msg "and here"
`
function ouch {
echo "Fail @ [${MY_NAME}:]"
exit 1
}
ouch $LINENO
`
$LINENOfor the current line number
$0for the current file. I used basenameto ensure you only get the file name and not the path.
$LINENO为$0当前文件的当前行号
。我曾经basename确保你只得到文件名而不是路径。
UPDATE:
更新：
2010-06-16.15:33:13.069 xx[11]: here
2010-06-16.15:33:13.073 xx[14]: and here
You have to pass the line as a parameter if you use the function approach else you will get the line of the function definition.
如果您使用函数方法，则必须将该行作为参数传递，否则您将获得函数定义的行。
回答by Kevin Little
I find the "BASH_SOURCE" and "BASH_LINENO" built-in arrays very useful:
我发现“BASH_SOURCE”和“BASH_LINENO”内置数组非常有用：
echo $LINENO
echo $(basename #!/bin/bash
debug() {
echo "${BASH_SOURCE[1]##*/}:${FUNCNAME[1]}[${BASH_LINENO[0]}]" > /dev/tty
}
debug
)
Invoking xx yields
调用 xx 收益
script:main[5]
回答by Loxley
You just need to
你只需要
# Say the file, line number and optional message for debugging
# Inspired by bash's `caller` builtin
# Thanks to https://unix.stackexchange.com/a/453153/143394
function yelp () {
# shellcheck disable=SC2154 # undeclared zsh variables in bash
if [[ $BASH_VERSION ]]; then
local file=${BASH_SOURCE[1]##*/} func=${FUNCNAME[1]} line=${BASH_LINENO[0]}
else # zsh
emulate -L zsh # because we may be sourced by zsh `emulate bash -c`
# $funcfiletrace has format: file:line
local file=${funcfiletrace[1]%:*} line=${funcfiletrace[1]##*:}
local func=${funcstack[2]}
[[ $func =~ / ]] && func=source # $func may be filename. Use bash behaviour
fi
echo "${file##*/}:$func:$line $*" > /dev/tty
}
回答by Tom Hale
Here's how to do it in a reusable function. if the following is in a file named script:
以下是如何在可重用函数中执行此操作。如果以下内容在名为 的文件中script：
This produces the output:
这会产生输出：
##代码##Which indicates the line on which debugwas called.
这表示debug被调用的行。
The following will print out the filename, function, line and an optional message.
以下将打印出文件名、函数、行和可选消息。
Also works in zshfor extra goodness.
也适用于zsh额外的好处。
