java 在 Spring 控制器上 $.ajax POST 后收到错误请求错误 (400)
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Receiving a Bad Request Error (400) after $.ajax POST on Spring Controller
提问by Abderrazak BOUADMA
Hello StackOverFlow(s)
你好 StackOverFlow
I'm running with this issue since more than 2 hours now It's simple
我从 2 个多小时以来一直在处理这个问题 很简单
I'm trying to send a JSON object to a Spring Controller by using a $.ajax POST call
我正在尝试使用 $.ajax POST 调用将 JSON 对象发送到 Spring Controller
I'm using AngularJS but that point is okey
我正在使用 AngularJS，但这一点很重要
here's the code of both server and client and the spring configuration
这是服务器和客户端的代码以及spring配置
Thank's in advance
提前致谢
JQuery :
查询：
$scope.push = function() {
$.ajax({
type: "PUT",
url:"rest/todo/greeting/",
data : {id:"1",title:"ajax",description:"ajax"},
dataType: "json",
contentType : "application/json",
success : function(data) {
$log.info(data)
}
})
}
Spring Controller :
弹簧控制器：
@Controller
@RequestMapping("/todo")
public class TodoController {
@RequestMapping(value = "/greeting", method = RequestMethod.PUT,consumes="application/json",produces="text/html")
public @ResponseBody String push(@RequestBody Todo todo) {
System.out.println(todo.getTitle());
return "test";
}
}
}
Spring Configuration :
弹簧配置：
<mvc:annotation-driven />
<context:component-scan base-package="org.lab.todo.controller" />
<bean id="defaultViews" class="org.springframework.web.servlet.view.json.MappingHymanson2JsonView" />
web.xml :
网页.xml :
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
<listener>
<listener-class>
org.springframework.web.context.ContextLoaderListener
</listener-class>
</listener>
<!--
Spring WEBMVC/REST Controllers
-->
<servlet>
<servlet-name>todo-dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>todo-dispatcher</servlet-name>
<url-pattern>/rest/*</url-pattern>
</servlet-mapping>
Ajax Call Update :
Ajax 调用更新：
$scope.push = function() {
var jsonString = {id:"1",title:"ajax",description:"ajax"};
var Todo = function(){}
Todo.id = "id";
Todo.title = "ajax";
Todo.description = "ajax";
$.post("rest/todo/greeting",JSON.stringify(Todo),function(response){console.log(response)},'json');
}
Fiddle Raw Request Header :
小提琴原始请求标头：
POST http://localhost:8080/todo-rest/rest/todo/greeting HTTP/1.1
Host: localhost:8080
Connection: keep-alive
Content-Length: 0
Accept: application/json, text/javascript, */*; q=0.01
Origin: http://localhost:8080
X-Requested-With: XMLHttpRequest
User-Agent: Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.17 (KHTML, like Gecko) Chrome/24.0.1312.56 Safari/537.17
Referer: http://localhost:8080/todo-rest/
Accept-Encoding: gzip,deflate,sdch
Accept-Language: en-US,en;q=0.8,fr;q=0.6
Accept-Charset: UTF-8,*;q=0.5
Fiddle Response Header
小提琴响应头
HTTP/1.1 415 Unsupported Media Type
Server: Apache-Coyote/1.1
Content-Type: text/html;charset=utf-8
Content-Length: 1048
Date: Thu, 31 Jan 2013 17:11:40 GMT
回答by Abderrazak BOUADMA
Here's the answer
这是答案
It's simply a matter of properly writing the JSON string
这只是正确编写 JSON 字符串的问题
instead of
代替
var jsonString = {id:"1",title:"ajax",description:"ajax"};
I wrote it like this
我是这样写的
var jsonString = '{"id":"1","title":"ajax","description":"ajax"}';
what is still weird is that JSON.stringify(MyObject) seems not to work in my case !!
仍然奇怪的是 JSON.stringify(MyObject) 在我的情况下似乎不起作用！
回答by Sotirios Delimanolis
If you're getting a 400 status code, it can only be for the following reason (from W3):
如果您收到 400 状态代码，则只能出于以下原因（来自W3）：
10.4.1 400 Bad Request
The request could not be understood by the server due to malformed syntax. The client SHOULD NOT repeat the request without modifications.
10.4.1 400 错误请求
由于语法格式错误，服务器无法理解该请求。客户端不应该在没有修改的情况下重复请求。
With Spring, this either means that the ajax request is wrong (see my comment about the data JSON string) or it can't parse and translate the JSON String in the request body to your command object Todo. So Spring has a method it can call, your push()method, but it doesn't have the parameter your are looking for to pass to it, so it throws a 400 Bad Request.
对于 Spring，这要么意味着 ajax 请求是错误的（请参阅我对数据 JSON 字符串的评论），要么它无法解析请求正文中的 JSON 字符串并将其转换为您的命令对象Todo。所以 Spring 有一个可以调用的push()方法，你的方法，但它没有你正在寻找传递给它的参数，所以它会抛出一个 400 Bad Request。
415 Unsupported Media Typemeans that Spring cannot find a method to consume what you are sending. Your push()Spring method consumes="application/json"but your request isn't using that content-type.
415 Unsupported Media Type意味着 Spring 找不到使用您发送的内容的方法。您的push()Spring 方法，consumes="application/json"但您的请求未使用该内容类型。
回答by Kurt Du Bois
Could you post your web.xml? Since you're not defining a suffix for your request and place a slash in the end, you're doing a request to the index.jsp of that directory.
你能发布你的 web.xml 吗？由于您没有为请求定义后缀并在末尾放置一个斜杠，因此您正在向该目录的 index.jsp 发出请求。
