在 windows 中创建后台进程
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Create a background process in windows
提问by Jumbo
How do I make a process go the background programatically?
如何以编程方式使进程进入后台？
What I want is for the user to double-click the process executable, and it just goes into the background ... and does not open a window while executing.
我想要的是让用户双击进程可执行文件，它只是进入后台......并且在执行时不打开窗口。
Any code snippet in visual c++ would be very helpful
Visual C++ 中的任何代码片段都会非常有帮助
回答by Cody Gray
Have you considered creating a Windows Serviceinstead? They're specifically designed to run in the background without showing a UI.
您是否考虑过创建Windows 服务？它们专门设计为在后台运行而不显示 UI。
Otherwise, just create an application without a window.
否则，只需创建一个没有 window 的应用程序。
回答by Brian Clapper
This might help: http://ss64.com/nt/start.html
这可能会有所帮助：http: //ss64.com/nt/start.html
回答by Adam Douglass
I know this is old, but I thought I would post something for when people find this through search.
我知道这是旧的，但我想我会发布一些东西，当人们通过搜索找到它时。
While I like Cody Gray's answer for design correctness, sometimes you don't have a choice.
虽然我喜欢 Cody Gray 对设计正确性的回答，但有时您别无选择。
If you want to launch a program without jumping to the new window (it appears in the background or minimized) or not create a window at all try looking at the ShellExecuteand ShellExecuteExfunctions. The argument nShowCmd(or nShow) gives you (among others) the options:
如果您想启动程序而不跳转到新窗口（它出现在后台或最小化）或根本不创建窗口，请尝试查看ShellExecute和ShellExecuteEx函数。参数nShowCmd(or nShow) 为您提供（除其他外）选项：
SW_HIDE
Hides the window and activates another window.
SW_SHOWMINNOACTIVE
Displays the window as a minimized window. The active window remains active.
SW_HIDE
隐藏窗口并激活另一个窗口。
SW_SHOWMINNOACTIVE
将窗口显示为最小化窗口。活动窗口保持活动状态。
As the documentation says, SW_HIDEcreates a process running the executable you give it, but if this program would normally create a window, none appears.
正如文档所说，SW_HIDE创建一个运行您提供的可执行文件的进程，但如果该程序通常会创建一个窗口，则不会出现任何窗口。
回答by user3451413
I tried this way and it worked fine: Create a console application and write your codes in the sub main as any other console application. Now change the application type in the project properties to windows Forms application from Console application thats it
我试过这种方法，效果很好：创建一个控制台应用程序，并像任何其他控制台应用程序一样在 sub main 中编写代码。现在将项目属性中的应用程序类型从控制台应用程序更改为 windows Forms 应用程序
