php 如何让 json_encode() 与 ISO-8859-1 (???) 一起工作
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How to get json_encode() to work with ISO-8859-1 (???)
提问by Johan
json_encode()wont work for me when I'm using ???. Why? And how can I get it to work?
json_encode()当我使用时对我不起作用？？？。为什么？我怎样才能让它工作？
The php:
的php：
echo json_encode($arr);
The javascript:
的javascript：
var theResponse = JSON.parse(xmlHttp.responseText);
When I alert()the response, and the response contains ?, ? or ?, the response is = NULL
当我alert()响应时，响应中包含 ?, ? 或 ?，响应为 =NULL
Please, help me out...
请帮帮我...
采纳答案by Johan
As Greg mentioned, I had to encode ??? to UTF-8. But I did't use iconv or mbstring. When I utf8_encode()all values before putting the values to the arraythe problem was solved.
正如格雷格提到的，我必须编码？？？到UTF-8。但我没有使用 iconv 或 mbstring。当我将utf8_encode()所有值放入值之前array，问题就解决了。
回答by Greg
It says in the json_encode()documentation:
它在json_encode()文档中说：
This function only works with UTF-8 encoded data.
此函数仅适用于 UTF-8 编码数据。
回答by Paul Phillips
This function will cast the correct data type for the JSON output and utf8_encode the strings.
此函数将为 JSON 输出转换正确的数据类型并对字符串进行 utf8_encode。
/* Change data-type from string to integar or float if required.
* If string detected then utf8_encode() it. */
function cast_data_types ($value) {
if (is_array($value)) {
$value = array_map('cast_data_types',$value);
return $value;
}
if (is_numeric($value)) {
if(strpos('.', $value)===false) return (float)$value;
return (int) $value;
}
return utf8_encode((string)$value);
}
json_encode (cast_data_types($data));
回答by Bernd Ott
JSON defines strings as Unicode!
JSON 将字符串定义为 Unicode！
You have to encode you ISO to UTF-8
您必须将 ISO 编码为 UTF-8
回答by Michael Butler
Old question, but figured I'd put this here in case someone needs to log data using json_encode but keep the data untouched, intact for inspection later.
老问题，但我想我会把它放在这里，以防有人需要使用 json_encode 记录数据但保持数据不变，以备日后检查。
You can encode the data raw using base64_encode, then it will work with json_encode. Later after running json_decode, you can decode the string with base64_decode, you'll get the original data unmodified.
您可以使用 对原始数据进行编码base64_encode，然后它将与json_encode. 稍后运行json_decode，您可以使用 解码字符串base64_decode，您将获得未修改的原始数据。
回答by George
As of PHP 5.4.0:
从 PHP 5.4.0 开始：
Convert your strings in your array to into utf-8using utf8_encode($str)function.
将数组中的字符串转换为utf-8usingutf8_encode($str)函数。
Then json_encodewith JSON_UNESCAPED_UNICODEoption:
然后json_encode使用JSON_UNESCAPED_UNICODE选项：
$arr = json_encode($array, JSON_UNESCAPED_UNICODE);
$arr = json_encode($array, JSON_UNESCAPED_UNICODE);
回答by Fabio Montefuscolo
The $data(in my case) is an array with text values as ISO-8859-1. The trick below prepares $datato be used with json_encode.
的$data（在我的情况）是文本值数组作为ISO-8859-1。下面的技巧准备$data与json_encode.
function toUtf8(&$v, $k) {
$v = utf8_encode($v);
}
array_walk_recursive($data, 'toUtf8');
回答by BennyBechDk
Using the standard method when reading from MySQL:
从 MySQL 读取时使用标准方法：
$resultArray = array();
while($obj = MySQL_fetch_object($res)) {
$resultArray[] = $obj;
}
$result = json_encode($resultArray);
The encoding can be done using the following:
可以使用以下方法进行编码：
$resultArray = array();
while($obj = MySQL_fetch_object($res)) {
foreach($obj as $key => $value) {
if (!is_null($value)) {
$obj->$key = utf8_encode($value);
}
}
$resultArray[] = $obj;
}
$result = json_encode($resultArray);
The if is_nullhas to be included so that null fields (e.g., DateTime fields) remain null in the output.
在if is_null必须被包括在内，以便空字段（例如，日期时间字段）保持空在输出中。
