vb.net 生成一个随机布尔值
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Generate a random boolean
提问by Christian Sauer
I am a little stuck with a simple Question: how to generate a simple random Boolean?
If am correct, a Boolean 0 = false and 1 = true, but how to suse that?
我有点被一个简单的问题困住了：如何生成一个简单的随机布尔值？
如果是正确的， a Boolean 0 = false and 1 = true，但如何使用它？
Current code:
当前代码：
Dim RandGen As New Random
Dim RandBool As Boolean
RandBool = Boolean.Parse(RandGen.Next(0, 1).tostring)
回答by Caramiriel
Or just simply:
或者只是简单地：
Random rng = new Random();
bool randomBool = rng.Next(0, 2) > 0;
Saves some processing power of parsing text, whereas a simple compare is enough.
节省一些解析文本的处理能力，而简单的比较就足够了。
Edit: Second parameter is exclusive, so should be .Next(0, 2).
编辑：第二个参数是独占的，所以应该是.Next(0, 2).
回答by Technikminer
Dim RandGen As New Random
Dim RandGen 作为新随机
Dim RandBool As Boolean
RandBool = RandGen.Next(0, 2).ToString
TextBox1.Text = RandBool
回答by Christian Lennartsson
Maybe something like this?
也许是这样的？
string[] trueOrFalse = { "false", "true"};
bool RandBool = bool.Parse(trueOrFalse[RandGen.Next(0,2)]);
