C# 如何使用 List<T> 填充数据表
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How to fill a datatable with List<T>
提问by MikaAK
How can convert a list to a datatable
如何将列表转换为数据表
[Serializable]
public class Item
{
public string Name { get; set; }
public double Price { get; set; }
public string @URL { get; set; }
public Item(string Name, string Price, string @URL)
{
this.Name = Name;
this.Price = Convert.ToDouble(Price);
this.@URL = @URL;
}
public override string ToString()
{
return this.Name;
}
}
I tried using:
我尝试使用：
static DataTable ConvertToDatatable(List<Item> list)
{
DataTable dt = new DataTable();
dt.Columns.Add("Name");
dt.Columns.Add("Price");
dt.Columns.Add("URL");
foreach (var item in list)
{
dt.Rows.Add(item.Name, Convert.ToString(item.Price), item.URL);
}
return dt;
}
Now I'm getting a box show up but its empty! Help!! What can i do to make the box actually have data?
现在我看到一个盒子出现，但它是空的！帮助！！我该怎么做才能使盒子真正拥有数据？
回答by Alex Wiese
Try this
尝试这个
static DataTable ConvertToDatatable(List<Item> list)
{
DataTable dt = new DataTable();
dt.Columns.Add("Name");
dt.Columns.Add("Price");
dt.Columns.Add("URL");
foreach (var item in list)
{
var row = dt.NewRow();
row["Name"] = item.Name;
row["Price"] = Convert.ToString(item.Price);
row["URL"] = item.URL;
dt.Rows.Add(row);
}
return dt;
}
回答by Michael Brown
I also had to come up with an alternate solution, as none of the options listed here worked in my case. I was using an IEnumerable and the underlying data was a IEnumerable and the properties couldn't be enumerated. This did the trick:
我还必须想出一个替代解决方案，因为这里列出的选项都不适用于我的情况。我使用的是 IEnumerable 并且底层数据是 IEnumerable 并且无法枚举属性。这做到了：
// remove "this" if not on C# 3.0 / .NET 3.5
public static DataTable ConvertToDataTable<T>(this IEnumerable<T> data)
{
List<IDataRecord> list = data.Cast<IDataRecord>().ToList();
PropertyDescriptorCollection props = null;
DataTable table = new DataTable();
if (list != null && list.Count > 0)
{
props = TypeDescriptor.GetProperties(list[0]);
for (int i = 0; i < props.Count; i++)
{
PropertyDescriptor prop = props[i];
table.Columns.Add(prop.Name, Nullable.GetUnderlyingType(prop.PropertyType) ?? prop.PropertyType);
}
}
if (props != null)
{
object[] values = new object[props.Count];
foreach (T item in data)
{
for (int i = 0; i < values.Length; i++)
{
values[i] = props[i].GetValue(item) ?? DBNull.Value;
}
table.Rows.Add(values);
}
}
return table;
}
回答by immy
Just in case you have a nullable property in your class object:
以防万一您的类对象中有一个可为空的属性：
private static DataTable ConvertToDatatable<T>(List<T> data)
{
PropertyDescriptorCollection props = TypeDescriptor.GetProperties(typeof(T));
DataTable table = new DataTable();
for (int i = 0; i < props.Count; i++)
{
PropertyDescriptor prop = props[i];
if (prop.PropertyType.IsGenericType && prop.PropertyType.GetGenericTypeDefinition() == typeof(Nullable<>))
table.Columns.Add(prop.Name, prop.PropertyType.GetGenericArguments()[0]);
else
table.Columns.Add(prop.Name, prop.PropertyType);
}
object[] values = new object[props.Count];
foreach (T item in data)
{
for (int i = 0; i < values.Length; i++)
{
values[i] = props[i].GetValue(item);
}
table.Rows.Add(values);
}
return table;
}
