C++ 如何使用 Google 测试捕获断言？
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原文地址: http://stackoverflow.com/questions/3756422/
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How to catch an assert with Google test?
提问by Killrazor
I'm programming some unit test with the Google test framework. But I want to check whether some asserts are well placed and are useful. Is there a way to catch an assert in Google test?
我正在使用 Google 测试框架编写一些单元测试。但我想检查一些断言是否放置得当并且有用。有没有办法在 Google 测试中捕获断言？
Example code under test:
测试中的示例代码：
int factorial(int n){
assert(n >= 0);
//....
}
And then the test:
然后是测试：
#include <gtest/gtest.h>
TEST(FactorialTest,assertNegative){
EXPECT_ANY_THROW({
factorial(-1);
});
}
But EXPECT_ANY_THROWdoesn't catch the assert but only exceptions. I'm searching for a solution to catch asserts.
但EXPECT_ANY_THROW不会捕获断言，而只会捕获异常。我正在寻找捕获断言的解决方案。
采纳答案by Steve Jessop
Google test provides ASSERT_DEATH, EXPECT_DEATHand other related macros.
谷歌测试提供ASSERT_DEATH，EXPECT_DEATH等相关宏。
This question and What are Google Test, Death Testsare each other's answers. Does that make them duplicates, or not? ;-)
这个问题和什么是谷歌测试，死亡测试是对方的答案。这是否使它们重复？;-)
回答by Michael
EXPECT_FATAL_FAILURE(statement,text) and EXPECT_NONFATAL_FAILURE(statement,text) will only passif 'statement' invokes a failingASSERT_x or EXECT_x respectively.
EXPECT_FATAL_FAILURE(statement,text) 和 EXPECT_NONFATAL_FAILURE(statement,text)只有在 'statement' 分别调用失败的ASSERT_x 或 EXECT_x时才会通过。
These statements will pass in your tests:
这些语句将通过您的测试：
EXPECT_NONFATAL_FAILURE( EXPECT_TRUE( 0 ), "" );
EXPECT_FATAL_FAILURE( ASSERT_TRUE( 0 ), "" );
EXPECT_NONFATAL_FAILURE( EXPECT_TRUE( 0 ), "" );
EXPECT_FATAL_FAILURE( ASSERT_TRUE( 0 ), "" );
