Java：如何找到给定字符串中最长的单词？

Java: How to find the longest word in a given String?

提问by Suraj

In a given string, I want to find the longest word and print the same.

在给定的字符串中，我想找到最长的单词并打印相同的单词。

The output I get is the second longest word, i.e "Today", but I should get "Happiest".
May I know what I am doing wrong or is there a better/different way to find the longest word in a string?

我得到的输出是第二长的单词，即"Today"，但我应该得到"Happiest".
我可以知道我做错了什么，还是有更好/不同的方法来找到字符串中最长的单词？

public class DemoString 
{
    public static void main(String[] args) 
    {
        String s="Today is the happiest day of my life";
        String[] word=s.split(" ");
        String longword=" ";
        for(int i=0;i<word.length;i++){
            for(int j=1+i;j<word.length;j++){
                if(word[i].length()>=word[j].length()){
                    longword=word[i];
                }
            }
        }
        System.out.println(longword+" is longest word with "+longword.length()+" characters");
        System.out.println(rts.length());
    }
}

回答by tt_emrah

instead it should be:

相反，它应该是：

for(int i=0 ; i<word.length ; i++)
{
    if(word[i].length() >= rts.length())
    {
        rts = word[i];
    }
}

回答by MSD

You can try like ,

你可以试试，

  String s="Today is the happiest day of my life";
  String[] word=s.split(" ");
  String rts=" ";
  for(int i=0;i<word.length;i++){
     if(word[i].length()>=rts.length()){
       rts=word[i];
     }
  }
  System.out.println(rts);
  System.out.println(rts.length());

回答by Madhavi

for(int i=0;i<word.length;i++){
            for(int j=0;j<word.length;j++){
                if(word[i].length()>=word[j].length()){
                   if(word[j].length()>=rts.length()) {
                      rts=word[j];
                   }
                } else if(word[i].length()>=rts.length()){
                   rts=word[i];
                }

            }
        }

回答by shash678

Here is a one-liner you can use with Java 8:

这是您可以在 Java 8 中使用的单行代码：

import java.util.*;

class Main {
  public static void main(String[] args) {
    String s = "Today is the happiest day of my life";
    System.out.println(Arrays.stream(s.split(" ")).max(Comparator.comparingInt(String::length)).orElse(null));
  }
}

Output:

输出：

happiest

Try it here!

在这里试试吧！

回答by Vivekanandan V

    String s= "Today is the happiest day of my life by vijayakumar";
           String [] word = s.split(" ");
    String maxlethWord = "";
    for(int i = 0; i < word.length; i++){
            if(word[i].length() >= maxlethWord.length()){
                  maxlethWord = word[i];
            } 
    }
     System.out.println(maxlethWord);  

回答by Supun Dharmarathne

Try this one.

试试这个。

   public static void main( String[] args )
    {
        String s = "Today is the happiest day of my life";
        String[] word = s.split( " " );
        String rts = " ";

        for ( int i = 0; i < word.length; i++ )
        {
            if ( word[i].length() > rts.length() )
                rts = word[i];

        }
        System.out.println( rts );
    }

回答by TanvirChowdhury

// the below Java Program will find Smallest and Largest Word in a String

// 下面的 Java 程序将在字符串中找到最小和最大的单词

class SmallestAndLargestWord 
{ 

    static String minWord = "", maxWord = ""; 

    static void minMaxLengthWords(String input)  
    { 
        // minWord and maxWord are received by reference  
        // and not by value 
        // will be used to store and return output 
        int len = input.length(); 
        int si = 0, ei = 0; 
        int min_length = len, min_start_index = 0, 
              max_length = 0, max_start_index = 0; 

        // Loop while input string is not empty 
        while (ei <= len)  
        { 
            if (ei < len && input.charAt(ei) != ' ') 
            { 
                ei++; 
            }  
            else
            { 
                // end of a word 
                // find curr word length 
                int curr_length = ei - si; 

                if (curr_length < min_length)  
                { 
                    min_length = curr_length; 
                    min_start_index = si; 
                } 

                if (curr_length > max_length)  
                { 
                    max_length = curr_length; 
                    max_start_index = si; 
                } 
                ei++; 
                si = ei; 
            } 
        } 

        // store minimum and maximum length words 
        minWord = input.substring(min_start_index, min_start_index + min_length); 
        maxWord = input.substring(max_start_index, max_length); 
    } 

    // Driver code 
    public static void main(String[] args) 
    { 
        String a = "GeeksforGeeks A Computer Science portal for Geeks"; 

        minMaxLengthWords(a); 

        // to take input in string use getline(cin, a); 
        System.out.print("Minimum length word: "
                + minWord 
                + "\nMaximum length word: "
                + maxWord); 
    } 
} 

**

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Input : "GeeksforGeeks A computer Science portal for Geeks"
Output : Minimum length word: A
         Maximum length word: GeeksforGeeks

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