在 C# 中除法以获得精确值
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Division in C# to get exact value
提问by Irannabi
If I divide 150 by 100, I should get 1.5. But I am getting 1.0 when I divided like I did below:
如果我将 150 除以 100，我应该得到 1.5。但是当我像下面那样划分时，我得到了 1.0：
double result = 150 / 100;
Can anyone tell me how to get 1.5?
谁能告诉我如何获得1.5？
回答by Aniket Inge
double result = (150.0/100.0)
One or both numbers should be a float/double on the right hand side of =
一个或两个数字应该是右侧的浮点数/双精度数 =
回答by MattW
Cast one of the ints to a floating point type. You should look into the difference between decimal and double and decide which you want, but to use double:
将其中一个整数转换为浮点类型。您应该研究十进制和双精度之间的区别并决定您想要哪个，但要使用双精度：
double result = (double)150 / 100;
回答by Mayank
Make the number float
做号码 float
var result = 150/100f
or you can make any of number to float by adding .0:
或者您可以通过添加.0以下内容使任何数字浮动：
double result=150.0/100
or
或者
double result=150/100.0
回答by Heinrich
try:
尝试：
double result = (double)150/100;
When you are performing the division as before:
当您像以前一样执行除法时：
double result = 150/100;
The devision is first done as an Int and then it gets cast as a double hence you get 1.0, you need to have a double in the equation for it to divide as a double.
该除法首先作为一个 Int 完成，然后它被转换为一个双精度数，因此您得到 1.0，您需要在等式中有一个双精度数才能将其除为双精度数。
回答by Jason Whitish
If you're just using literal values like 150 and 100, C# is going to treat them as integers, and integer math always "rounds down". You can add a flag like "f" for float or "m" for decimal to not get integer math. So for example result = 150m/100mwill give you a different answer than result = 150/100.
如果你只是使用像 150 和 100 这样的字面值，C# 会将它们视为整数，并且整数数学总是“四舍五入”。您可以为浮点数添加“f”之类的标志，或为十进制添加“m”之类的标志，以免获得整数数学。因此，例如result = 150m/100m会给你一个不同的答案result = 150/100。
