java 如何从给定的整数值中获取 Alphabet？

Question

提问by M.M.RAM KUMAR

How to get alphabets by the numeric postion in java ?

如何通过java中的数字位置获取字母？

Suppose i have entered 1 then as a output i need to get A how can i get the alphabets position in java?

假设我输入了 1 然后作为输出我需要得到 A 我怎样才能在 java 中获得字母位置？

Thanks in advance.

提前致谢。

Answer 1

Try this

试试这个

int i = 1;
System.out.println((char)(i+'A'-1));

Answer 2

int charValue = 1; //this is the number you enter
char letter = (char)(charValue+64);  //this is the character you want

For lowercase letters, use (charValue+96)

对于小写字母，使用 (charValue+96)

Answer 3

You could use a switch/case statementto manually get each letter however a better solution would be to use the ASCII table to get the letters.

您可以使用switch/case 语句手动获取每个字母，但更好的解决方案是使用 ASCII 表来获取字母。

public char getLetter(int i)
{
  return (char) (i + 64);
}

The above function would return 'A' when i is 1

当 i 为 1 时，上述函数将返回 'A'

Answer 4

You have letters/characters, think of them as positions in an array.

您有字母/字符，将它们视为数组中的位置。

int number = 0;
String[] array = new String[] {"a", "b", "c", "..."};
String letter = array[number + 1];