C# WPF 弹出窗口
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WPF popup window
提问by Joe SHI
I would like to let the user choose their options after a button is clicked. For example, showing two buttons, "Restart Now" and "Restart Later" in a modal popup window would be my preference. Using a MessageBoxis not a solution for me as it does not allow the user to change the title of buttons.
我想让用户在单击按钮后选择他们的选项。例如，在模态弹出窗口中显示两个按钮“立即重启”和“稍后重启”将是我的偏好。使用 aMessageBox对我来说不是解决方案，因为它不允许用户更改按钮的标题。
采纳答案by Botz3000
You need to create a new Window class. You can design that then any way you want. You can create and show a window modally like this:
您需要创建一个新的 Window 类。你可以按照你想要的任何方式设计它。您可以像这样以模态方式创建和显示窗口：
MyWindow popup = new MyWindow();
popup.ShowDialog();
You can add a custom property for your result value, or if you only have two possible results ( + possibly undeterminate, which would be null), you can set the window's DialogResultproperty before closing it and then check for it (it is the value returned by ShowDialog()).
您可以为结果值添加自定义属性，或者如果您只有两个可能的结果（+ 可能不确定，这将是null），您可以DialogResult在关闭窗口之前设置窗口的属性，然后检查它（它是由ShowDialog()）。
回答by Harry
Simply show a new window with two buttons. Add property to contain user result.
只需显示一个带有两个按钮的新窗口。添加属性以包含用户结果。
回答by Nickon
In WPF there is a control named Popup.
在 WPF 中有一个名为 Popup 的控件。
Popup myPopup = new Popup();
//(...)
myPopup.IsOpen = true;
回答by Karthik Krishna Baiju
XAML
XAML
<Popup Name="myPopup">
<TextBlock Name="myPopupText"
Background="LightBlue"
Foreground="Blue">
Popup Text
</TextBlock>
</Popup>
c#
C＃
Popup codePopup = new Popup();
TextBlock popupText = new TextBlock();
popupText.Text = "Popup Text";
popupText.Background = Brushes.LightBlue;
popupText.Foreground = Brushes.Blue;
codePopup.Child = popupText;
you can find more details about the Popup Control from MSDN documentation.
您可以从 MSDN 文档中找到有关弹出控件的更多详细信息。
