javascript 在数组中查找特定字符
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Finding a specific character in an array
提问by isolatedhowl
So let's say I have an array that looks like this:
因此，假设我有一个如下所示的数组：
weather = ["sun", "clouds", "rain", "hail", "snow"]
And I want to find and display all of the strings which have the letter "s" in them. This is what I think I should do...
我想找到并显示所有包含字母“s”的字符串。这是我认为我应该做的...
for(var i = 0; i < weather.length; i++)
{
if(weather[i].indexOf('s') != -1)
{
alert(weather);
}
}
But that just displays all of the weather strings as many times as there are strings with the letter "s" in them. (It will just alert: "sun, clouds, rain, hail, snow" 3 times)
但这只是显示所有天气字符串的次数与其中包含字母“s”的字符串一样多。（它只会提醒：“太阳，云，雨，冰雹，雪”3次）
How do I get it to alert just the specific names of the weather which contain the letter "s"?
我如何让它只提醒包含字母“s”的天气的特定名称？
回答by karthikr
You need to do alert(weather[i])instead of alert(weather)
你需要做alert(weather[i])而不是alert(weather)
Check this fiddle
检查这个小提琴
回答by dandavis
as simple modern solution without vars or loops:
作为没有变量或循环的简单现代解决方案：
alert(
["sun", "clouds", "rain", "hail", "snow"].filter(/./.test, /i/)
)
回答by isolatedhowl
Oh. I think I was just missing a small detail.
哦。我想我只是错过了一个小细节。
for(var i = 0; i < weather.length; i++)
{
if(weather[i].indexOf('s') != -1)
{
alert(weather[i]);
}
}
回答by Upvesh Kumar
very simple
很简单的
weather = ["sun", "clouds", "rain", "hail", "snow"];
weather.forEach(function(arrayItem,arrayIndex,array){
if(array[arrayIndex].match('s')){
alert(array[arrayIndex]);
}
})
Explanation:
解释：
forEach() method calls a function for each element in the array.
arraytItem like='sun' , 'clouds' etc.
arrayIndex=position of arrayItem;
array=weather;
forEach() 方法为数组中的每个元素调用一个函数。
arraytItem like='sun' , 'clouds' 等
arrayIndex=arrayItem 的位置；
数组=天气；
