Dropdown onchange 调用 PHP 函数
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Dropdown onchange calling PHP Function
提问by Mark James
What i'm attempting to do with the below code is call a PHP function from an dropdown menu.
我试图用下面的代码做的是从下拉菜单中调用一个 PHP 函数。
Is there a clean way of doing this?
有没有干净的方法来做到这一点？
code:
代码：
<html>
<head>
</head>
<body>
<?php
function OnSelectionChange() {
echo("OK IT WORKS");
}
?>
<section>
<select onchange="OnSelectionChange()">
<option value='' disabled selected>Assign Driver</option>
<option value='4353'>Steve Jobs</option>
<option value='3333'>Ian Wright</option>
<option value='66666'>Mark James</option>
</select>
</section>
</body>
</html>
回答by vivekcs0114
You can get the selected value from the drop down list simply using php without using JavaScript.
您只需使用 php 即可从下拉列表中获取所选值，而无需使用 JavaScript。
<html>
<head>
<title>Country</title>
</head>
<body>
<form>
Select Your Country
<select name="country" onchange="this.form.submit()">
<option value="" disabled selected>--select--</option>
<option value="india">India</option>
<option value="us">Us</option>
<option value="europe">Europe</option>
</select>
</form>
<?php
if(isset($_GET["country"])){
$country=$_GET["country"];
echo "select country is => ".$country;
}
?>
</body>
</html>回答by Santhy K
simple ajax using jquery
使用jquery的简单ajax
index page
索引页
<!DOCTYPE html>
<html>
<head>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.1.1/jquery.min.js"></script>
<script>
$(document).ready(function(){
$('#myDropDown').change(function(){
//Selected value
var inputValue = $(this).val();
alert("value in js "+inputValue);
//Ajax for calling php function
$.post('submit.php', { dropdownValue: inputValue }, function(data){
alert('ajax completed. Response: '+data);
//do after submission operation in DOM
});
});
});
</script>
</head>
<body>
<select id="myDropDown">
<option value='' disabled selected>Assign Driver</option>
<option value='4353'>Steve Jobs</option>
<option value='3333'>Ian Wright</option>
<option value='66666'>Mark James</option>
</select>
</body>
</html>
in submit.php
在提交.php
<?php
function processDrpdown($selectedVal) {
echo "Selected value in php ".$selectedVal;
}
if ($_POST['dropdownValue']){
//call the function or execute the code
processDrpdown($_POST['dropdownValue']);
}
for simple js ajax use XMLHttpRequest
对于简单的 js ajax 使用XMLHttpRequest
回答by JungKyungSuk
Does not connect onchange event with php function. must use javascript function
不使用 php 函数连接 onchange 事件。必须使用javascript函数
<script>
function OnSelectionChange()
{
alert("OK IT WORKS");
}
</script>
回答by Elliott Sadgamer
Can't do that, use JavaScript function instead
不能这样做，请改用 JavaScript 函数
<html>
<head>
</head>
<body>
<script>
function OnSelectionChange()
{
alert("OK IT WORKS");
}
</script>
<section>
<select onchange="OnSelectionChange()">
<option value='' disabled selected>Assign Driver</option>
<option value='4353'>Steve Jobs</option>
<option value='3333'>Ian Wright</option>
<option value='66666'>Mark James</option>
</select>
</section>
</body>
</html>
回答by Prmaja Co.
<html>
<head>
<title>Country</title>
</head>
<body>
<form>
Select Your Country
<select name="country" onchange="this.form.submit()">
<option value="" disabled selected>--select--</option>
<option value="india">India</option>
<option value="us">Us</option>
<option value="europe">Europe</option>
</select>
</form>
<?php
if(isset($_GET["country"])){
$country=$_GET["country"];
echo "select country is => ".$country;
}
?>
</body>
</html>