php 提取字符串PHP中两个字符之间的子字符串
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Extract a substring between two characters in a string PHP
提问by Sebastian
Is there a PHP function that can extract a phrase between 2 different characters in a string? Something like substr();
是否有一个 PHP 函数可以提取字符串中 2 个不同字符之间的短语？类似的东西substr()；
Example:
例子：
$String = "[modid=256]";
$First = "=";
$Second = "]";
$id = substr($string, $First, $Second);
Thus $idwould be 256
这样$id就会256
Any help would be appreciated :)
任何帮助，将不胜感激 ：）
回答by Yogesh Suthar
use this code
使用此代码
$input = "[modid=256]";
preg_match('~=(.*?)]~', $input, $output);
echo $output[1]; // 256
working example http://codepad.viper-7.com/0eD2ns
回答by MaxEcho
Use:
用：
<?php
$str = "[modid=256]";
$from = "=";
$to = "]";
echo getStringBetween($str,$from,$to);
function getStringBetween($str,$from,$to)
{
$sub = substr($str, strpos($str,$from)+strlen($from),strlen($str));
return substr($sub,0,strpos($sub,$to));
}
?>
回答by cartina
$String = "[modid=256]";
$First = "=";
$Second = "]";
$Firstpos=strpos($String, $First);
$Secondpos=strpos($String, $Second);
$id = substr($String , $Firstpos, $Secondpos);
回答by tasmaniski
If you don't want to use reqular expresion, use strstr, trimand strrevfunctions:
如果您不想使用 reqular 表达式，请使用strstr、trim和strrev函数：
// Require PHP 5.3 and higher
$id = trim(strstr(strstr($String, '='), ']', true), '=]');
// Any PHP version
$id = trim(strrev(strstr(strrev((strstr($String, '='))), ']')), '=]');
回答by Prasanth Bendra
$str = "[modid=256]";
preg_match('/\[modid=(?P<modId>\d+)\]/', $str, $matches);
echo $matches['modId'];
回答by Gerald Schneider
Regular Expression is your friend.
正则表达式是你的朋友。
preg_match("/=(\d+)\]/", $String, $matches);
var_dump($matches);
This will match any number, for other values you will have to adapt it.
这将匹配任何数字，对于其他值，您必须对其进行调整。
回答by Bgi
You can use a regular expression:
您可以使用正则表达式：
<?php
$string = "[modid=256][modid=345]";
preg_match_all("/\[modid=([0-9]+)\]/", $string, $matches);
$modids = $matches[1];
foreach( $modids as $modid )
echo "$modid\n";
回答by tillinberlin
(moved from comment because formating is easier here)
（从评论中移出，因为这里的格式更容易）
might be a lazy approach, but in such cases i usually would first explode my string like this:
可能是一种懒惰的方法，但在这种情况下，我通常会首先像这样分解我的字符串：
$string_array = explode("=",$String);
and in a second step i would get rid of that "]" maybe through rtrim:
在第二步中，我可能会通过 rtrim 摆脱那个“]”：
$id = rtrim($string_array[1], "]");
...but this will onlywork if the structure is always exactly the same...
...但这只有在结构始终完全相同的情况下才有效......
-cheers-
-干杯-
ps: shouldn't it actually be $String = "[modid=256]";?
ps：它实际上不应该是$String = "[modid=256]"; ?
回答by Reshil
Try Regular Expression
试试正则表达式
$String =" [modid=256]";
$result=preg_match_all('/(?<=(=))(\d+)/',$String,$matches);
print_r($matches[0]);
Output
输出
Array ( [0] => 256 )
数组 ( [0] => 256 )
ExplanationHere its used the Positive Look behind (?<=)in regular expression eg (?<=foo)bar matches bar when preceded by foo, here (?<=(=))(\d+) we match the (\d+) just after the '=' sign. \d Matches any digit character (0-9). + Matches 1 or more of the preceeding token
解释这里它使用了正则表达式中 (?<=) 后面的 Positive Look，例如 (?<=foo)bar 在 foo 前面匹配 bar，这里 (?<=(=))(\d+) 我们匹配 (\d+ ) 就在 '=' 符号之后。\d 匹配任何数字字符 (0-9)。+ 匹配 1 个或多个前面的标记
回答by pacmora
You can use a regular expression or you can try this:
您可以使用正则表达式，也可以试试这个：
$String = "[modid=256]";
$First = "=";
$Second = "]";
$posFirst = strpos($String, $First); //Only return first match
$posSecond = strpos($String, $Second); //Only return first match
if($posFirst !== false && $posSecond !== false && $posFirst < $posSecond){
$id = substr($string, $First, $Second);
}else{
//Not match $First or $Second
}
You should read about substr. The best way for this is a regular expression.
你应该阅读 substr。最好的方法是使用正则表达式。
