Java 如何在正则表达式中匹配“任何字符”？
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How to match "any character" in regular expression?
提问by Saobi
The following should be matched:
应符合以下条件：
AAA123
ABCDEFGH123
XXXX123
can I do: ".*123"?
我能做：".*123"？
采纳答案by Delan Azabani
Yes, you can. That should work.
是的你可以。那应该工作。
.= any char\.= the actual dot character.?=.{0,1}= match any char zero or one times.*=.{0,}= match any char zero or more times.+=.{1,}= match any char one or more times
.= 任何字符\.= 实际的点字符.?==.{0,1}匹配任何字符零次或一次.*==.{0,}匹配任何字符零次或多次.+==.{1,}匹配任何字符一次或多次
回答by thr
Use the pattern .to match any character once, .*to match any character zero or more times, .+to match any character one or more times.
使用模式.匹配任意字符一次，.*匹配任意字符零次或多次， .+匹配任意字符一次或多次。
回答by Huusom
No, *will match zero-or-more characters. You should use +, which matches one-or-more instead.
不，*将匹配零个或多个字符。您应该使用+, 它匹配一个或多个。
This expression might work better for you: [A-Z]+123
这个表达式可能更适合你： [A-Z]+123
回答by polygenelubricants
There are lots of sophisticated regex testing and development tools, but if you just want a simple test harness in Java, here's one for you to play with:
有许多复杂的正则表达式测试和开发工具，但如果您只想要一个简单的 Java 测试工具，这里有一个供您使用：
String[] tests = {
"AAA123",
"ABCDEFGH123",
"XXXX123",
"XYZ123ABC",
"123123",
"X123",
"123",
};
for (String test : tests) {
System.out.println(test + " " +test.matches(".+123"));
}
Now you can easily add new testcases and try new patterns. Have fun exploring regex.
现在您可以轻松添加新测试用例并尝试新模式。玩得开心探索正则表达式。
See also
也可以看看
回答by BlueRaja - Danny Pflughoeft
Yes that will work, though note that .will not match newlines unless you pass the DOTALLflag when compiling the expression:
是的，这会起作用，但请注意，.除非在编译表达式时传递DOTALL标志，否则不会匹配换行符：
Pattern pattern = Pattern.compile(".*123", Pattern.DOTALL);
Matcher matcher = pattern.matcher(inputStr);
boolean matchFound = matcher.matches();
回答by Ravi Shekhar
Try the regex .{3,}. This will match all characters except a new line.
试试正则表达式.{3,}。这将匹配除新行之外的所有字符。
回答by Akash Kumar Seth
Specific Solution to the example problem:-
示例问题的具体解决方案：-
Try [A-Z]*123$will match 123, AAA123, ASDFRRF123. In case you need at least a character before 123use [A-Z]+123$.
尝试[A-Z]*123$将匹配123, AAA123, ASDFRRF123。如果您在123使用前至少需要一个字符[A-Z]+123$。
General Solution to the question (How to match "any character" in the regular expression):
问题的一般解决方案（如何匹配正则表达式中的“任何字符”）：
- If you are looking for anything including whitespace you can try
[\w|\W]{min_char_to_match,}. - If you are trying to match anything except whitespace you can try
[\S]{min_char_to_match,}.
- 如果您正在寻找包括空格在内的任何内容，您可以尝试
[\w|\W]{min_char_to_match,}. - 如果您尝试匹配除空格以外的任何内容，您可以尝试
[\S]{min_char_to_match,}.
回答by Abrahan Gonzalez
I work this Not always dot is means any char. Exception when single line mode. \p{all}should be
我的工作并不总是点是任何字符。单行模式时例外。\p{all}应该
String value = "|°?<>!\"#$%&/()=?'\??/*-+_@[]^^{}";
String expression = "[a-zA-Z0-9\p{all}]{0,50}";
if(value.matches(expression)){
System.out.println("true");
} else {
System.out.println("false");
}
回答by Jamie Davis
The most common way I have seen to encode this is with a character class whose members form a partition of the set of all possible characters.
我见过的最常见的编码方式是使用字符类，其成员构成所有可能字符集的一个分区。
Usually people write that as [\s\S](whitespace or non-whitespace), though [\w\W], [\d\D], etc. would all work.
通常人们写为[\s\S]（空格或无空格），但是[\w\W]，[\d\D]等一切都能解决。
回答by Anonymous
[^]should match any character, including newline. [^CHARS]matches all characters except for those in CHARS. If CHARSis empty, it matches all characters.
[^]应该匹配任何字符，包括换行符。[^煤焦]所有字符匹配除了那些在煤焦。如果CHARS为空，则匹配所有字符。
JavaScript example:
JavaScript 示例：
/a[^]*Z/.test("abcxyz ##代码##\r\n\t012789ABCXYZ") // Returns ‘true'.
