C++ 二进制转十进制？
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C++ Binary to decimal?
提问by S?ren Eriksen
I made a function that converts binary numbers to decimals, but if i go to high on the binary numbers, it just returns 256??? What could cause this? I'm using int variables. Any help would be really appreciated
我做了一个将二进制数转换为十进制数的函数，但是如果我对二进制数进行高位，它只会返回 256 ？？？什么可能导致这种情况？我正在使用 int 变量。任何帮助将非常感激
#include <iostream>
using namespace std;
int FromBin (int n)
{
int increment;
int Result;
increment = 1;
Result = 0;
while(n != 0)
{
if (n % 10 == 1){
Result = Result+increment;
n = n-1;
}
n = n/10;
increment = increment*2;
}
cout<<Result;
}
void ToBin(int n)
{
if (n / 2 != 0) {
ToBin(n / 2);
}
cout<<n % 2;
}
int main()
{
int choice;
int n;
cout<<"Choose a function: press 0 for decimals to binary, press 1 for binary to decimal\n";
cin>>choice;
if (choice == 0){
cout<<"Enter a number: \n";
cin>>n;
ToBin(n);
}
else if (choice == 1){
cout<<"Enter a number: \n";
cin>>n;
FromBin(n);
}
else{
cout<<"Invalid input";
}
}
I'm new to C++ so I don't understand this... :/
我是 C++ 新手，所以我不明白这一点......：/
回答by alexkrause88
This is a cool program you got going on here... This is what I found for a possible solution to your problem...
这是你在这里进行的一个很酷的程序......这是我为你的问题找到的可能解决方案......
/* C++ program to convert binary number into decimal */
#include <iostream>
using namespace std;
int main()
{
long bin, dec = 0, rem, num, base = 1;
cout << "Enter the binary number(1s and 0s) : ";
cin >> num;
bin = num;
while (num > 0)
{
rem = num % 10;
dec = dec + rem * base;
base = base * 2;
num = num / 10;
}
cout << "The decimal equivalent of " << bin << " : " << dec << endl;
return 0;
}
回答by Cory Kramer
回答by Tomcatus
From your comment I can see that you are trying to use it on a number that is just too large for an int variable. Look for limits, as for int I found that maximal value is 2147483647.
从您的评论中，我可以看到您正试图在一个对于 int 变量来说太大的数字上使用它。寻找限制，至于 int 我发现最大值是 2147483647。
