如何在 Python 3 中比较两个字符串中的单个字符
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How to compare individual characters in two strings in Python 3
提问by Hymanie
I'm trying to compare the first character of two different strings (and so on) to form a new string based on those results. This is what I've tried using, however its comparing every element of each list to each other.
我正在尝试比较两个不同字符串（等等）的第一个字符，以根据这些结果形成一个新字符串。这是我尝试使用的，但是它将每个列表的每个元素相互比较。
def compare(a,b):
s = ""
for x in a:
for y in b:
if x == y:
s+=str(x)
else:
s+=str(y)
It seems like such a simple question but I'm stuck.
这似乎是一个如此简单的问题，但我被卡住了。
采纳答案by L3viathan
Use zip:
使用邮编：
def compare(a, b):
for x, y in zip(a, b):
if x == y:
...
回答by Prune
Are you perhaps looking for something with logic similar to this? It chooses the alphabetically earlier character from each input string:
您是否正在寻找与此逻辑类似的东西？它从每个输入字符串中选择按字母顺序较早的字符：
def compare(a,b):
s = ""
for i in range(len(a)):
if a[i] < b[i]:
s+=str(a[i])
else:
s+=str(b[i])
return s
print compare ("seven", "eight")
Output:
输出：
eegen
The one-line version of this is
这个的单行版本是
return ''.join(a[i] if a[i] < b[i] else b[i] for i in range(len(a)))
回答by Newb_01
input(x)
input(y)
cnt = 0
for char_val in x:
if b[cnt] == char_val:
print("match")
else:
print("mis-match")
