php 警告：尝试分配非对象的属性，但对象存在

Warning: Attempt to assign property of non-object, but the Object exists

提问by marcusds

This is my class:

这是我的课：

class Network {
    protected $value = null;
    protected $properties = array();
    public $type = null;

    function __construct($value = null, $type = null) {
        $this->value = $value;
        $this->type = $type;
    }

    public function __set($name, $value) {
        if(isset($this->{$name})) {
            $this->{$name} = $value;
        } else {
            $this->properties[$name] = new self($value, null);
        }
    }

    public function __get($name) {
        return $this->properties[$name]->value;
    }

    public function __toString() {
        return $this->value;
    }
}

This is what I am trying to do:

这就是我想要做的：

$networks = new \stdClass();
$networks->test= new \Orange_Post\Network('Test');
$networks->test->enabled = true;
$networks->test->enabled->type = 'boolean';

But I get the error:

但我收到错误：

Warning:Attempt to assign property of non-object on the last line, $networks->test->enabled->type = 'boolean';

警告：尝试在最后一行分配非对象的属性，$networks->test->enabled->type = 'boolean';

This is my first attempt at branching out and doing something like this, and I just can't figure out what I am doing incorrectly.

这是我第一次尝试扩展并做这样的事情，我只是无法弄清楚我做错了什么。

回答by Rizier123

So what is going on here?

那么这里发生了什么？

$networks = new \stdClass();
$networks->test= new \Orange_Post\Network('Test');
$networks->test->enabled = true;
$networks->test->enabled->type = 'boolean';
 ↑         ↑     ↑        ↑ Tries to access a property of a value ('TRUE')
 |         |     | 'enabled' as property never exists     
 |         | Is a property with an instance of '\Orange_Post\Network'
 | Is an instance of '\stdClass'

First off, when you try to assign trueto the property enabled. Then __set()gets called, since the property doesn't exists.

首先，当您尝试分配true给属性时enabled。然后__set()被调用，因为该属性不存在。

public function __set($name, $value) {
    if(isset($this->{$name})) {
        $this->{$name} = $value;
    } else {
        $this->properties[$name] = new self($value, null);
    }
}

In that magic method you assign a new instace of the class itself to the property array propertiesand use the name (enabled) as index.

在那个神奇的方法中，您将类本身的一个新实例分配给属性数组，properties并使用名称 ( enabled) 作为索引。

$networks->test->enabled->type = 'boolean';

After this you try to set a property typeto the property enabled. Here __getgets invoked.

在此之后，您尝试type为该属性设置一个属性enabled。这里__get被调用。

public function __get($name) {
    return $this->properties[$name]->value;
}

So now you simply return the array value of propertiesand return the property valueof it. And the property valueis not an object. Just remove the ->valuepart and your code will return the object.

所以现在你只需返回数组的值properties并返回value它的属性。并且该属性value不是对象。只需删除该->value部分，您的代码就会返回该对象。

In other words your last line:

换句话说，你的最后一行：

$networks->test->enabled->type = 'boolean';

Becomes:

变成：

$networks->test->properties["enabled"]->value->type = 'boolean';
                 ↑                      ↑ This is causing the problem
                 | Holds an object      | Holds 'true' as property value

回答by Mark Schaschke

You are assigning the enabledproperty a value of true, however the next line is trying to treat that property as an object (it's not, it's a boolean value). If you really need to have a value and type for the enabledproperty, try this instead:

您正在为该enabled属性分配一个值true，但是下一行试图将该属性视为一个对象（不是，它是一个布尔值）。如果您确实需要为该enabled属性设置值和类型，请尝试以下操作：

$networks->test->enabled = new \stdClass();
$networks->test->enabled->value = true;
$networks->test->enabled->type = 'boolean';

Hope this helps!

希望这可以帮助！