bash 运行文件夹中的所有 shell 脚本
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Run all shell scripts in folder
提问by code123
I have many .shscripts in a single folder and would like to run them one after another. A single script can be execute as:
我.sh在一个文件夹中有许多脚本，并且想一个接一个地运行它们。单个脚本可以执行为：
bash wget-some_long_number.sh -H
Assume my directory is /dat/dat1/files
假设我的目录是 /dat/dat1/files
How can I run bash wget-some_long_number.sh -Hone after another?
我怎样才能bash wget-some_long_number.sh -H一个接一个地运行？
I understand something in these line should work:
我知道这些行中的某些内容应该有效：
for i in *.sh;...do ....; done
for i in *.sh;...do ....; done
回答by Kirill Bulygin
Use this:
用这个：
for f in *.sh; do # or wget-*.sh instead of *.sh
bash "$f" -H
done
If you want to stop the whole execution when a script fails:
如果您想在脚本失败时停止整个执行：
for f in *.sh; do
bash "$f" -H || break # execute successfully or break
# Or more explicitly: if this execution fails, then stop the `for`:
# if ! bash "$f" -H; then break; fi
done
It you want to run, e.g., x1.sh, x2.sh, ..., x10.sh:
你想运行，例如，x1.sh, x2.sh, ..., x10.sh：
for i in `seq 1 10`; do
bash "x$i.sh" -H
done
回答by Hamza Jabbour
there is a much simpler way, you can use the run-partscommand which will execute all scripts in the folder:
有一种更简单的方法，您可以使用run-parts将执行文件夹中所有脚本的命令：
run-parts /path/to/folder
回答by Caucasian Malaysian
I ran into this problem where I couldn't use loops and run-parts works with cron.
我遇到了这个问题，我无法使用循环和运行部分与 cron 一起工作。
Answer:
回答：
foo () {
bash -H
#echo
#cat
}
cd /dat/dat1/files #change directory
export -f foo #export foo
parallel foo ::: *.sh #equivalent to putting a & in between each script
You use GNU parallel, this executes everything in the directory, with the added buff of it happening at a lot faster rate. Not to mention it isn't just with script execution, you could put any command in the function and it'll work.
您使用 GNU 并行，这会执行目录中的所有内容，并以更快的速度增加它的增益。更不用说它不仅仅是脚本执行，你可以在函数中放置任何命令，它会起作用。
