C# 设置自定义异常的消息而不将其传递给基本构造函数

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时间:2020-08-10 10:12:57  来源:igfitidea点击:

Setting the message of a custom Exception without passing it to the base constructor

c#visual-studioexceptionvisual-studio-2012

提问by Dirk Boer

I want to make a custom Exception in C#, but in theory I do need to do a little parsing first before I can make a human readable ExceptionMessage.

我想在 C# 中创建一个自定义异常,但理论上我确实需要先做一些解析,然后才能创建人类可读的 ExceptionMessage。

The problem is that the orginal Message can only be set by calling the base constructor of Messsage, so I can't do any parsing in advance.

问题是只能通过调用 的基本构造函数来设置原始消息Messsage,因此我无法提前进行任何解析。

I tried overring the Message property like this:

我尝试像这样覆盖 Message 属性:

public class CustomException : Exception
{
    string _Message;

    public CustomException(dynamic json) : base("Plep")
    {
        // Some parsing to create a human readable message (simplified)
        _Message    = json.message;
    }

    public override string Message
    {
        get { return _Message; }
    }
}

The problem is that the Visual Studio debugger still shows the message that I've passed into the constructor, Plepin this case.

问题是 Visual Studio 调试器仍然显示我传递给构造函数的消息,在本例中为Plep

throw new CustomException( new { message="Show this message" } )

results in:

结果是:

Visual Studio Exception Dialog

Visual Studio 异常对话框

If I leave the base constructor empty it will show a very generic message:

如果我将基本构造函数留空,它将显示一条非常通用的消息:

An unhandled exception of type 'App.CustomException' occurred in App.exe

App.exe 中发生类型为“App.CustomException”的未处理异常

Question

It looks like the Exception Dialog reads some field/property that I don't have any access too. Is there any other way to set a human readable error message outside the base constructor on Exception.

看起来异常对话框读取了一些我也没有任何访问权限的字段/属性。有没有其他方法可以在 Exception 上的基本构造函数之外设置人类可读的错误消息。

Note that I'm using Visual Studio 2012.

请注意,我使用的是 Visual Studio 2012。

采纳答案by Sebastian Redl

Just put the formatting code into a static method?

只是将格式化代码放入静态方法中?

public CustomException(dynamic json) : base(HumanReadable(json)) {}
private static string HumanReadable(dynamic json) {
    return whatever you need to;
}

回答by nvoigt

Consider the Microsoft Guidelines for creating new exceptions:

考虑创建新例外的 Microsoft 指南:

  using System;
  using System.Runtime.Serialization;

  [Serializable]
  public class CustomException : Exception
  {
    //
    // For guidelines regarding the creation of new exception types, see
    //    https://msdn.microsoft.com/en-us/library/ms229064(v=vs.100).aspx
    //

    public CustomException()
    {
    }

    public CustomException(string message) : base(message)
    {
    }

    public CustomException(string message, Exception inner) : base(message, inner)
    {
    }

    protected CustomException(SerializationInfo info, StreamingContext context) : base(info, context)
    {
    }

    public static CustomException FromJson(dynamic json)
    {
      string text = ""; // parse from json here

      return new CustomException(text);
    }
  }

Note the static factory method (not part of the pattern), that you can use in your program like this:

请注意静态工厂方法(不是模式的一部分),您可以像这样在程序中使用它:

throw CustomException.FromJson(variable);

That way you followed best practice and can parse your json inside the exception class.

这样您就遵循了最佳实践,并且可以在异常类中解析您的 json。

回答by Ferruccio

I think the problem may be with the Visual Studio debugger. I got the same exact results you got using the debugger, but when I print the message instead:

我认为问题可能出在 Visual Studio 调试器上。我得到了与使用调试器得到的完全相同的结果,但是当我打印消息时:

class CustomException : Exception {
    public CustomException(dynamic json)
        : base("Plep") {
            _Message = json.message;
    }

    public override string Message {
        get { return _Message; }
    }

    private string _Message;
}

class Program {
    static void Main(string[] args) {
        try {
            throw new CustomException(new { message = "Show this message" });
        } catch (Exception ex) {
            Console.WriteLine(ex.Message);
        }
    }
}

I get the expected "Show this message".

我得到了预期的"Show this message".

If you put a breakpoint where the Exception is caught, the debugger does show you the correct message.

如果在捕获异常的位置放置断点,调试器会向您显示正确的消息。

回答by Simons0n

I like to use this here. It is easy and does not need the static function:

我喜欢在这里使用它。这很简单,不需要静态函数:

public class MyException : Exception
{
    public MyException () : base("This is my Custom Exception Message")
    {
    }
}

回答by Kieran Foot

What's wrong with something like this.

这样的事情有什么问题。

    public class FolderNotEmptyException : Exception
{

    public FolderNotEmptyException(string Path) : base($"Directory is not empty. '{Path}'.")
    { }

    public FolderNotEmptyException(string Path, Exception InnerException) : base($"Directory is not empty. '{Path}'.", InnerException)
    { }

}

I just use a string and include parameters. Simple solution.

我只使用一个字符串并包含参数。简单的解决方案。