有没有办法将多个数组传递给 PHP json_encode 并用 jQuery 解析它？
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Is there a way to pass multiple arrays to PHP json_encode and parse it with jQuery?
提问by chromedude
Right now I have this PHP:
现在我有这个 PHP：
$columns = array(*/Data*/);
echo json_encode($columns);
And this is sent through an AJAX GET request with JQuery.
这是通过 JQuery 的 AJAX GET 请求发送的。
var columns = jQuery.parseJSON(response);
I would like to be able to send more than one array in the json_encode()is there any way to do this and how would you parse it with jQuery?
我希望能够发送多个数组，json_encode()有没有办法做到这一点，你将如何用 jQuery 解析它？
回答by Riyono
Sure, you could send an array of array. PHP associative array will become a javascript object.
当然，你可以发送一个数组数组。PHP 关联数组将成为一个 javascript 对象。
In PHP:
在 PHP 中：
$data = array();
$data['fruits'] = array('apple','banana','cherry');
$data['animals'] = array('dog', 'elephant');
echo json_encode($data);
and then on jQuery
然后在 jQuery 上
var data = jQuery.parseJSON(response);
then you could then do something like this to access the values
然后你可以做这样的事情来访问这些值
console.log(data.fruits[0]); // apple
console.log(data.animals[1]); // elephant
回答by zb'
The code should be like the following:
代码应如下所示：
$columns = array(/*Data*/);
$columns1 = array(/*Data1*/);
echo json_encode(array($columns,$columns1));
in jQuery use
在 jQuery 中使用
var columns_array=jQuery.parseJSON(response);
columns=columns_array[0];
columns1=columns_array[1];
回答by learner
$data1 = array();
$data2 = array();
$data1[] = array('apple','banana','cherry');
$data2[] = array('dog', 'elephant');
echo json_encode(array($data1,$data2));
in ajax,
在阿贾克斯中，
console.log(response[0][0])//apple
console.log(response[1][0])//dog.....
回答by uutsav
After you have populated all the arrays namely $array1_json, $array2_jsonetc in my case,
在您填写的所有阵列，即$array1_json，$array2_json等在我的情况，
$number_of_array1elements = count($array1_json);
$number_of_array2elements = count($array2_json);
$number_of_array3elements = count($array3_json);
array_unshift($array1_json , $number_of_array1elements);
// pushes element to the start of array1_json
array_unshift($array2_json , $number_of_array2elements);
array_unshift($array3_json , $number_of_array3elements);
and similarly for other arrays.
其他数组也类似。
echo json_encode( array_merge($array1_json, $array2_json, $array3_json) );
In your .js file, use:
在您的 .js 文件中，使用：
var val = xmlhttp.responseText;
var jsonData = JSON.parse(val);
var number_of_array1elements = jsonData[0];
for (var i = 1; i <= number_of_array1elements; i++ )
{
// use jsonData[i] to select the required element and do whatever is needed with it
}
var number_of_array2elements = jsonData[i];
for ( i = i+1; i <= number_of_array1elements+number_of_array2elements+1; i++ )
{
// use jsonData[i] to select the required element and do whatever is needed with it
}
