postgresql 将从具有不同模式的两个 SELECT 语句“生成”的结果连接到一个表中

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时间:2020-10-20 23:24:22  来源:igfitidea点击:

Join results "generated" from two SELECT statements with different schemas into one table

mysqlsqlpostgresql

提问by Martin Marinov

So I have the following SELECT statements:

所以我有以下 SELECT 语句:

SELECT COUNT(A.Award) AS US, SUBSTRING(CAST(M.Year as char(4)), 0 , 4)  AS Decade
FROM Movies M, Awards A
WHERE {SOME WHERE CLAUSE}
GROUP BY Decade;

and

SELECT COUNT(*) AS Total, SUBSTRING(CAST(A2.Year as char(4)), 0 , 4) AS Decade
FROM Awards A2
WHERE {SOME WHERE CLAUSE}
GROUP BY Decade;

The first one is "generating" a table with columns (US, Decade) and the second one is "generating" another table with columns (Total, Decade). I want to join those two tables so that I get a table (US, Total, Decade). How can I do it?

第一个是“生成”一个带有列(USDecade)的表,第二个是“生成”另一个带有列(TotalDecade)的表。我想加入这两个表,以便我得到一个表(USTotalDecade)。我该怎么做?

回答by knittl

Put them in subqueries and do a JOIN:

将它们放在子查询中并执行以下操作JOIN

SELECT a.US, a.decade, b.total FROM

  (SELECT COUNT(A.Award) AS US, SUBSTRING(CAST(M.Year as char(4)), 0 , 4)  AS Decade
  FROM Movies M, Awards A
  WHERE {SOME WHERE CLAUSE}
  GROUP BY Decade ) AS a

INNER JOIN

  (SELECT COUNT(*) AS Total, SUBSTRING(CAST(A2.Year as char(4)), 0 , 4) AS Decade
  FROM Awards A2
  WHERE {SOME WHERE CLAUSE}
  GROUP BY Decade) AS b

ON a.decade = b.decade