C语言 在 C 中打印字符的二进制表示
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Printing binary representation of a char in C
提问by user1783150
I want a really basic way to print out the binary representation of a char. I can't seem to find any example code anywhere.
我想要一种非常基本的方法来打印出一个字符的二进制表示。我似乎在任何地方都找不到任何示例代码。
I assumed you could do it in a few lines but everything I find is overly long and complex using lots of functions I haven't used before. atoicomes up a lot but it's not standard.
我假设你可以用几行代码来完成，但我发现的所有内容都使用了许多我以前没有使用过的功能，而且过于冗长和复杂。atoi出现了很多，但它不是标准的。
Is there a simple function or simple way of writing a function to take a char variable and then print out a binary representation?
是否有一个简单的函数或简单的方法来编写一个函数来获取一个 char 变量，然后打印出一个二进制表示？
Eg: char 'x' is the argument taken in by the function and "x is 0111 1000" is printed out.
例如：char 'x' 是函数接收的参数，打印出“x is 0111 1000”。
It's for a school assignment where I must take user input of a string and print out the string in binary. I just need to get the basics of converting a char to binary but i'm struggling at the moment.
这是一个学校作业，我必须接受用户输入的字符串并以二进制形式打印出字符串。我只需要了解将字符转换为二进制的基础知识，但目前我正在苦苦挣扎。
回答by alex
What you'd want to do is use bitwise operators to mask the bits one by one and print them to the standard output.
您想要做的是使用按位运算符一一屏蔽位并将它们打印到标准输出。
- A
charin C is guaranteed to be 1 byte, so loop to8. - Within each iteration, mask off the highest order bit.
- Once you have it, just print it to standard output.
charC 中的A保证为 1 个字节，因此循环到8.- 在每次迭代中，屏蔽掉最高位。
- 获得后，只需将其打印到标准输出即可。
Here is a quick stab which hopefully makes sense...
这是一个快速的尝试，希望有意义......
main() {
char a = 10;
int i;
for (i = 0; i < 8; i++) {
printf("%d", !!((a << i) & 0x80));
}
printf("\n");
return 0;
}
键盘。
In order to get the bit, I shift to the left to get the numbered bit (highest to lowest so printing it is easy) and then mask it off. I then translate it to 0or 1with !!.
为了获得该位，我向左移动以获得编号位（从最高到最低，因此打印很容易），然后将其屏蔽。然后，我把它翻译到0或1用!!。
回答by No Idea For Name
you can use this method
你可以用这个方法
const char *byte_to_binary(int x)
{
static char b[9];
b[0] = ' printf("%s\n", byte_to_binary(15));
';
int z;
for (z = 128; z > 0; z >>= 1)
{
strcat(b, ((x & z) == z) ? "1" : "0");
}
return b;
}
to get the binary representation and print with it
获取二进制表示并用它打印
for example
例如
void printBits(size_t const size, void const * const ptr)
{
unsigned char *b = (unsigned char*) ptr;
unsigned char byte;
int i, j;
for (i=size-1;i>=0;i--)
{
for (j=7;j>=0;j--)
{
byte = b[i] & (1<<j);
byte >>= j;
printf("%u", byte);
}
}
puts("");
}
int main(int argv, char* argc[])
{
int i = 23;
uint ui = UINT_MAX;
float f = 23.45f;
printBits(sizeof(i), &i);
printBits(sizeof(ui), &ui);
printBits(sizeof(f), &f);
return 0;
}
回答by Optimus Prime
#include <limits.h>
char *chartobin ( unsigned char c )
{
static char bin[CHAR_BIT + 1] = {0};
int i;
for( i = CHAR_BIT - 1; i >= 0; i-- )
{
bin[i] = (c % 2) + '0';
c /= 2;
}
return bin;
}
回答by Rahul Tripathi
Try this:-
尝试这个：-
##代码##