如何使用跨度设置 PHP 回声输出的样式
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How to style PHP echo output with span
提问by Blackline
I'm trying to style the output of each echo.
我正在尝试为每个回声的输出设置样式。
Ideally I'd like to use <span class=""> </span>for each echo, but I'm not too sure how to achieve this.
理想情况下，我想<span class=""> </span>用于每个回声，但我不太确定如何实现这一点。
$result = mysql_query("SELECT * FROM Blog");
while($row = mysql_fetch_array($result))
{
echo $row['Date'];
echo $row['Title'];
echo $row['Message'];
echo "<img src='".$row['Image']."'/>";
}
mysql_close($con);
回答by JvdBerg
$result = mysql_query("SELECT * FROM Blog");
while($row = mysql_fetch_array($result))
{
echo "<span class=\"myclass\">$row['Date']</span>";
echo "<span class=\"myclass\">$row['Title']</span>";
echo "<span class=\"myclass\">$row['Message']</span>";
echo "<img src='".$row['Image']."'/>";
}
mysql_close($con);
or, much nicer, in a table:
或者，更好的是，在表格中：
$result = mysql_query("SELECT * FROM Blog");
echo "<table>"
while($row = mysql_fetch_array($result)) {
echo "<tr>"
echo "<td>$row['Date']</td>";
echo "<td>$row['Title']</td>";
echo "<td>$row['Message']</td>";
echo "<td><img src='".$row['Image']."'/></td>";
echo "</tr>"
}
echo "</table>"
mysql_close($con);
You then can style each row and column with a class.
然后，您可以使用一个类来设置每一行和每一列的样式。
回答by John V.
Try this:
尝试这个：
$prepend = "<span class=''>";
$append = "</span>";
$result = mysql_query("SELECT * FROM Blog");
while($row = mysql_fetch_array($result))
{
echo $prepend.$row['Date'].$append;
echo $prepend.$row['Title'].$append;
echo $prepend. $row['Message'].$append;
echo $prepend."<img src='".$row['Image']."'/>".$append;
}
mysql_close($con);
回答by Ikke
I'd create a function that does this:
我将创建一个执行此操作的函数：
function decorated_echo($text) {
echo '<span class="myclass">' . $text . '</span>';
}
This way, you don't have to repeat this everytime you want this behaviour.
这样，您就不必每次想要这种行为时都重复此操作。
回答by luigif
You are guessing right, just add required html in the echo:
您猜对了，只需在回显中添加所需的 html：
echo '<span class="yourclass"><img src="'.$row['Image'].'" /></span>';
or you can just put inline style if no css file is loaded:
或者，如果没有加载 css 文件，您可以只放置内联样式：
echo '<span style="color:red;"><img src="'.$row['Image'].'" /></span>';
