javascript 如何从电子邮件地址检索姓名
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How to retrieve Name from Email Address
提问by leeshin
With javascript, how do we remove the @gmail.com or @aol.com from a string so that what only remains is the name?
使用javascript，我们如何从字符串中删除@gmail.com 或@aol.com，以便只剩下名称？
var string = "[email protected]";
Will be just "johdoe"? I tried with split but it did not end well. thanks.
会只是“johdoe”吗？我尝试了 split 但它并没有很好地结束。谢谢。
回答by Roko C. Buljan
var email = "[email protected]";
var name = email.substring(0, email.lastIndexOf("@"));
var domain = email.substring(email.lastIndexOf("@") +1);
console.log( name ); // john.doe
console.log( domain ); // email.com
The above will also work for validnames containing @(tools.ietf.org/html/rfc3696Page 5)
以上也适用于包含（tools.ietf.org/html/rfc3696 Page 5）的有效名称@
john\@doe
"john@@".doe
"j@hn".d\@e
john\@doe
"john@@".doe
"j@hn".d\@e
回答by Joseph Myers
You should take note that a valid email address is an incredibly sophisticated object and may contain multiple @signs (ref. http://cr.yp.to/im/address.html).
您应该注意，有效的电子邮件地址是一个非常复杂的对象，可能包含多个@符号（参考http://cr.yp.to/im/address.html）。
"The domain part of an address is everything after the final
@."
“地址的域部分是最终
@.之后的一切。”
Thus, you should do something equivalent to:
因此，您应该执行以下操作：
var email = "[email protected]";
var name = email.substring(0, email.lastIndexOf("@"));
or even shorter,
甚至更短，
var name = email.replace(/@[^@]+$/, '');
If you want both the name and the domain/hostname, then this will work:
如果您想要名称和域/主机名，那么这将起作用：
var email = "[email protected]";
var lasta = email.lastIndexOf('@');
var name, host;
if (lasta != -1) {
name = email.substring(0, lasta);
host = email.substring(lasta+1);
/* automatically extends to end of string when 2nd arg omitted */
} else {
/* respond to invalid email in some way */
}
回答by Wtower
And another alternative using split:
使用split 的另一种选择：
var email = "[email protected]";
var sp = email.split('@');
console.log(sp[0]); // john.doe
console.log(sp[1]); // email.com
回答by Atish Dipongkor - MVP
Try it using substring()and indexOf()
尝试使用substring()和indexOf()
var name = email.substring(0, email.indexOf("@"));
回答by Atish Dipongkor - MVP
var email = "[email protected]";
email=email.replace(/@.*/,""); //returns string (the characters before @)
回答by Manoj Kadolkar
You can try with the replace() and regular expression. You can read more about replace() using regex here
您可以尝试使用 replace() 和正则表达式。您可以在此处使用正则表达式阅读有关 replace() 的更多信息
var myEmail = '[email protected]';
var name= myEmail.replace(/@.*/, "");
console.log(name);
This returns the string before @
这将返回@ 之前的字符串
回答by Jonth Sm
As shown in How to remove or get domain name from an e-mail address in Javascript?, you can do it using the following code:
如如何在 Javascript 中从电子邮件地址中删除或获取域名？，您可以使用以下代码执行此操作：
const getDomainFromEmail = email => {
let emailDomain = null;
const pos = email.search('@'); // get position of domain
if (pos > 0) {
emailDomain = email.slice(pos+1); // use the slice method to get domain name, "+1" mean domain does not include "@"
}
return emailDomain;
};
const yourEmail = "[email protected]"
console.log(getDomainFromEmail(yourEmail));
// result : 4codev.com
