我在 PHP 中有 2 个日期，如何运行 foreach 循环来完成所有这些日子？
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I have 2 dates in PHP, how can I run a foreach loop to go through all of those days?
提问by Shamoon
I'm starting with a date 2010-05-01and ending with 2010-05-10. How can I iterate through all of those dates in PHP?
我以日期开始2010-05-01并以2010-05-10. 如何在 PHP 中遍历所有这些日期？
回答by Gordon
Requires PHP5.3:
需要 PHP5.3：
$begin = new DateTime('2010-05-01');
$end = new DateTime('2010-05-10');
$interval = DateInterval::createFromDateString('1 day');
$period = new DatePeriod($begin, $interval, $end);
foreach ($period as $dt) {
echo $dt->format("l Y-m-d H:i:s\n");
}
This will output all days in the defined period between $startand $end. If you want to include the 10th, set $endto 11th. You can adjust format to your liking. See the PHP Manual for DatePeriod.
这将输出$start和之间定义的时间段内的所有天数$end。如果要包括第 10 个，请设置$end为第 11 个。您可以根据自己的喜好调整格式。请参阅DatePeriod的 PHP 手册。
回答by Sabri Aziri
This also includes the last date
这也包括最后日期
$begin = new DateTime( "2015-07-03" );
$end = new DateTime( "2015-07-09" );
for($i = $begin; $i <= $end; $i->modify('+1 day')){
echo $i->format("Y-m-d");
}
If you dont need the last date just remove =from the condition.
如果您不需要最后日期，只需=从条件中删除。
回答by Harold1983-
Converting to unix timestamps makes doing date math easier in php:
转换为 unix 时间戳使得在 php 中进行日期数学更容易：
$startTime = strtotime( '2010-05-01 12:00' );
$endTime = strtotime( '2010-05-10 12:00' );
// Loop between timestamps, 24 hours at a time
for ( $i = $startTime; $i <= $endTime; $i = $i + 86400 ) {
$thisDate = date( 'Y-m-d', $i ); // 2010-05-01, 2010-05-02, etc
}
When using PHP with a timezone having DST, make sure to add a time that is not 23:00, 00:00 or 1:00 to protect against days skipping or repeating.
使用带有 DST 的时区的 PHP 时，请确保添加不是 23:00、00:00 或 1:00 的时间，以防止跳过或重复天数。
回答by Alexander Kharchenko
Copy from php.net sample for inclusiverange:
从包含范围的php.net 示例复制：
$begin = new DateTime( '2012-08-01' );
$end = new DateTime( '2012-08-31' );
$end = $end->modify( '+1 day' );
$interval = new DateInterval('P1D');
$daterange = new DatePeriod($begin, $interval ,$end);
foreach($daterange as $date){
echo $date->format("Ymd") . "<br>";
}
回答by Mark Baker
$startTime = strtotime('2010-05-01');
$endTime = strtotime('2010-05-10');
// Loop between timestamps, 1 day at a time
$i = 1;
do {
$newTime = strtotime('+'.$i++.' days',$startTime);
echo $newTime;
} while ($newTime < $endTime);
or
或者
$startTime = strtotime('2010-05-01');
$endTime = strtotime('2010-05-10');
// Loop between timestamps, 1 day at a time
do {
$startTime = strtotime('+1 day',$startTime);
echo $startTime;
} while ($startTime < $endTime);
回答by HADI
Here is another simple -
这是另一个简单的 -
/**
* Date range
*
* @param $first
* @param $last
* @param string $step
* @param string $format
* @return array
*/
function dateRange( $first, $last, $step = '+1 day', $format = 'Y-m-d' ) {
$dates = [];
$current = strtotime( $first );
$last = strtotime( $last );
while( $current <= $last ) {
$dates[] = date( $format, $current );
$current = strtotime( $step, $current );
}
return $dates;
}
Example:
例子：
print_r( dateRange( '2010-07-26', '2010-08-05') );
Array (
[0] => 2010-07-26
[1] => 2010-07-27
[2] => 2010-07-28
[3] => 2010-07-29
[4] => 2010-07-30
[5] => 2010-07-31
[6] => 2010-08-01
[7] => 2010-08-02
[8] => 2010-08-03
[9] => 2010-08-04
[10] => 2010-08-05
)
回答by user2182143
User this function:-
使用此功能：-
function dateRange($first, $last, $step = '+1 day', $format = 'Y-m-d' ) {
$dates = array();
$current = strtotime($first);
$last = strtotime($last);
while( $current <= $last ) {
$dates[] = date($format, $current);
$current = strtotime($step, $current);
}
return $dates;
}
Usage / function call:-
用法/函数调用：-
Increase by one day:-
增加一天：-
dateRange($start, $end); //increment is set to 1 day.
Increase by Month:-
按月增加：-
dateRange($start, $end, "+1 month");//increase by one month
use third parameter if you like to set date format:-
如果您想设置日期格式，请使用第三个参数：-
dateRange($start, $end, "+1 month", "Y-m-d H:i:s");//increase by one month and format is mysql datetime
回答by Jean Souza
here's a way:
这是一种方法：
$date = new Carbon();
$dtStart = $date->startOfMonth();
$dtEnd = $dtStart->copy()->endOfMonth();
$weekendsInMoth = [];
while ($dtStart->diffInDays($dtEnd)) {
if($dtStart->isWeekend()) {
$weekendsInMoth[] = $dtStart->copy();
}
$dtStart->addDay();
}
The result of $weekendsInMoth is array of weekend days!
$weekendsInMoth 的结果是周末天数的数组！
回答by zukayu
$date = new DateTime($_POST['date']);
$endDate = date_add(new DateTime($_POST['date']),date_interval_create_from_date_string("7 days"));
while ($date <= $endDate) {
print date_format($date,'d-m-Y')." AND END DATE IS : ".date_format($endDate,'d-m-Y')."\n";
date_add($date,date_interval_create_from_date_string("1 days"));
}
You can iterate like this also, The $_POST['date']can be dent from your app or website
Instead of $_POST['date']you can also place your string here "21-12-2019". Both will work.
你也可以像这样迭代，$_POST['date']可以从你的应用程序或网站中提取出来，而不是$_POST['date']你也可以把你的字符串放在这里"21-12-2019"。两者都会起作用。
回答by Victor Nu?ez
If you use Laravel and want to use Carbon the correct solution would be the following:
如果您使用 Laravel 并想使用 Carbon，正确的解决方案如下：
$start_date = Carbon::createFromFormat('Y-m-d', '2020-01-01');
$end_date = Carbon::createFromFormat('Y-m-d', '2020-01-31');
$period = new CarbonPeriod($start_date, '1 day', $end_date);
foreach ($period as $dt) {
echo $dt->format("l Y-m-d H:i:s\n");
}
Remember to add:
记得补充：
- use Carbon\Carbon;
- use Carbon\CarbonPeriod;
- 使用碳\碳；
- 使用碳\碳周期；
