jQuery 用连字符替换字符串中所有特殊字符和空格的正则表达式
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Regex for replacing all special characters and spaces in a string with hyphens
提问by user2643287
I have a string in which I need to replace all the special characters "~!@#$%^&*()_+=`{}[]|:;'<>,./?" and spaces with hyphens. Multiple special characters in a row should result in a single hyphen.
我有一个字符串，我需要在其中替换所有特殊字符 "~!@#$%^&*()_+=`{}[]|:;'<>,./?" 和带连字符的空格。一行中的多个特殊字符应生成一个连字符。
var mystring="Need !@#$%^\" to /replace this*(){}{}|\><? with_new string ";
// desired output: "Need-to-replace-this-with-new-string"
At present, I'm using this series of replace()calls:
目前，我正在使用这一系列的replace()调用：
return mystring.replace(/[^a-z0-9\s]/gi, '').replace(/[_\s]/g, '-').replace(/\//g, "-");
But it's outputting this:
但它输出的是：
Need----------to/replace-this--------with-new-string;
where it's adding a hyphen for every special character in the string except for the forward slash.
它为字符串中的每个特殊字符添加一个连字符，除了正斜杠。
回答by David says reinstate Monica
I'd suggest:
我建议：
var inputString = "~!@#$%^&*()_+=`{}[]|\:;'<>,./?Some actual text to keep, maybe...",
outputString = inputString.replace(/([~!@#$%^&*()_+=`{}\[\]\|\:;'<>,.\/? ])+/g, '-').replace(/^(-)+|(-)+$/g,'');
console.log(outputString);
回答by Paul Roub
Going by your comment and example:
根据您的评论和示例：
return mystring.trim().replace(/["~!@#$%^&*\(\)_+=`{}\[\]\|\:;'<>,.\/?"\- \t\r\n]+/g, '-');
or to replace allnon-alphanumeric characters:
或替换所有非字母数字字符：
return mystring.trim().replace(/[^a-z0-9]+/gi, '-');
You might also add:
您还可以添加：
.replace(/^-+/, '').replace(/-+$/, '');
to kill off any leading or trailing dashes (at which point you no longer need to call trim()).
消除任何前导或尾随的破折号（此时您不再需要调用trim()）。
Example:
例子：
function cleanUp(st) {
return st.
replace(/[^a-z0-9]+/gi, '-').
replace(/^-+/, '').
replace(/-+$/, '');
}
var mystring="Need !@#$%^\" to /replace this*(){}{}|\><? with_new string ";
console.log( cleanUp(mystring) );