Python - While-Loop直到列表为空
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Python - While-Loop until list is empty
提问by Adam Starrh
I'm working with Django and I have a queryset of objects that has been converted to a list (unpaid_sales). I'm executing a process that iterates through this list and operates on each item until either the list is empty, or a given integer (bucket) reaches zero.
我正在使用 Django，并且我有一个已转换为列表 ( unpaid_sales) 的对象查询集。我正在执行一个过程，该过程遍历此列表并对每个项目进行操作，直到列表为空或给定的整数 ( bucket) 达到零为止。
This is how I set it up:
我是这样设置的：
while unpaid_sales:
while bucket > 0:
unpaid_sale = unpaid_sales.pop(0)
...do stuff
In some cases, I am getting the following error:
在某些情况下，我收到以下错误：
pop from empty list
从空列表中弹出
What's wrong with my logic?
我的逻辑有什么问题？
采纳答案by tynn
Your end criteria must be formulated a little differently: loop while there are items and the bucketis positive. oris not the right operation here.
您的最终标准必须略有不同：循环时有项目并且bucket是正数。or在这里不是正确的操作。
while unpaid_sales and bucket > 0
unpaid_sale = unpaid_sales.pop(0)
#do stuff
回答by MMF
Do not use separate whileloops. Do as follows :
不要使用单独的while循环。执行以下操作：
while unpaid_sales and bucket > 0 :
unpaid_sale = unpaid_sales.pop(0)
...do stuff
回答by Efferalgan
You should do a single loop: while bucket>0 and unpaid_sales. Here, you are popping elements in the bucketloop, and then just just check that bucketis positive, but you do not check that element_salesstill has elements in it.
你应该做一个循环：while bucket>0 and unpaid_sales。在这里，您在bucket循环中弹出元素，然后只检查它bucket是否为正，但不检查其中是否element_sales仍有元素。
