php SimpleXML：选择具有特定属性值的元素
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SimpleXML: Selecting Elements Which Have A Certain Attribute Value
提问by dimo414
In an XML document, I have elements which share the same name, but the value of an attribute defines what type of data it is, and I want to select all of those elements which have a certain value from the document. Do I need to use XPath (and if so, could you suggest the right syntax) or is there a more elegant solution?
在 XML 文档中，我有共享相同名称的元素，但属性的值定义了它是什么类型的数据，我想从文档中选择所有具有特定值的元素。我是否需要使用 XPath（如果需要，您能否建议正确的语法）还是有更优雅的解决方案？
Here's some example XML:
这是一些示例 XML：
<object>
<data type="me">myname</data>
<data type="you">yourname</data>
<data type="me">myothername</data>
</object>
And I want to select the contents of all <data>tags children of <object>who's type is me.
我想选择who's type is的所有<data>标签的内容。<object>me
PS - I'm trying to interface with the Netflix API using PHP - this shouldn't matter for my question, but if you want to suggest a good/better way to do so, I'm all ears.
PS - 我正在尝试使用 PHP 与 Netflix API 进行交互 - 这对我的问题来说无关紧要，但是如果您想提出一个好的/更好的方法，我会全力以赴。
回答by Gumbo
Try this XPath:
试试这个 XPath：
/object/data[@type="me"]
So:
所以：
$myDataObjects = $simplexml->xpath('/object/data[@type="me"]');
And if objectis not the root of your document, use //object/data[@type="me"]instead.
如果object不是您文档的根目录，请//object/data[@type="me"]改用。
回答by willbradley
I just made a function to do this for me; it only grabs the first result though. Your mileage may vary.
我刚刚做了一个功能来为我做这件事；不过，它只获取第一个结果。你的旅费可能会改变。
function query_attribute($xmlNode, $attr_name, $attr_value) {
foreach($xmlNode as $node) {
switch($node[$attr_name]) {
case $attr_value:
return $node;
}
}
}
Usage:
用法：
echo query_attribute($MySimpleXmlNode->Customer, "type", "human")->Name;
(For the XML below)
（对于下面的 XML）
<Root><Customer type="human"><Name>Sam Jones</name></Customer></Root>
