jQuery 如何在jqgrid中获取所选行的行ID
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how to get row id of selected row in jqgrid
提问by Vishweshwar Kapse
I am writing this code and calling the method on rowdoubleclick of the jqgrid. I have also given all the tags and the column names of my jqgrid. Can you help me figure out why I am getting "undefined" when I alert the values?
我正在编写此代码并在 jqgrid 的 rowdoubleclick 上调用该方法。我还给出了我的 jqgrid 的所有标签和列名。你能帮我弄清楚为什么当我提醒值时我得到“未定义”吗？
<cc1:JQGrid ID="grdUserDetails" runat="server" Width="770px" Height="350px" ClientSideEvents-RowDoubleClick="ForwardDetails">
<Columns>
<cc1:JQGridColumn DataField="VisitorID" HeaderText="ID" TextAlign="Left" PrimaryKey="true"
Visible="false" Searchable="false">
</cc1:JQGridColumn>
<cc1:JQGridColumn DataField="PersonName" HeaderText="Visitor" TextAlign="Left">
</cc1:JQGridColumn>
<cc1:JQGridColumn DataField="CompanyName" HeaderText="Company Name" TextAlign="Left">
</cc1:JQGridColumn>
<cc1:JQGridColumn DataField="ContactNumber" HeaderText="Contact Number" TextAlign="Left">
</cc1:JQGridColumn>
<cc1:JQGridColumn DataField="Address" HeaderText="Address" TextAlign="Left">
</cc1:JQGridColumn>
<cc1:JQGridColumn DataField="Email" HeaderText="Email" TextAlign="Left">
</cc1:JQGridColumn>
<cc1:JQGridColumn DataField="DisplayDate" HeaderText="Last Visited on" TextAlign="Left">
</cc1:JQGridColumn>
</Columns>
<PagerSettings PageSize="15" PageSizeOptions="[15,25,50]" />
<ToolBarSettings ShowSearchButton="false" ShowRefreshButton="true" ShowSearchToolBar="true">
</ToolBarSettings>
<AppearanceSettings ShowRowNumbers="true" ></AppearanceSettings>
<SearchToolBarSettings SearchToolBarAction="SearchOnKeyPress" />
</cc1:JQGrid>
function ForwardDetails() {
var PersonName, Address, CompanyName, ContactNumber, Email;
var selectedRowId, cellValue;
var myGrid = $('#grdUserDetails');
selectedRowId = myGrid.jqGrid('getGridParam', 'selrow');
cellValue = myGrid.jqGrid('getCell', selectedRowId, 'Visitor Name');
window.opener.setValues(PersonName, Address, CompanyName, ContactNumber, Email);
window.close();
}
回答by Manish Mishra
try this:
尝试这个：
var myGrid = $('#list'),
selectedRowId = myGrid.jqGrid ('getGridParam', 'selrow'),
cellValue = myGrid.jqGrid ('getCell', selectedRowId, 'columnName');
where columnNameis the column you provided in the nameproperty of colModel
columnName您在name属性中提供的列在哪里colModel
and #listis the id of your grid.
并#list为您的网格的ID。
