Linux Bash 相对日期(x 天前)
声明:本页面是StackOverFlow热门问题的中英对照翻译,遵循CC BY-SA 4.0协议,如果您需要使用它,必须同样遵循CC BY-SA许可,注明原文地址和作者信息,同时你必须将它归于原作者(不是我):StackOverFlow
原文地址: http://stackoverflow.com/questions/4679046/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Bash relative date (x days ago)
提问by Dennis Thrys?e
I have a date string that I am able to parse and format with the date
command from a bash script.
我有一个日期字符串,我可以date
使用 bash 脚本中的命令对其进行解析和格式化。
But how can I determine how many days ago this date was from my script? I would like to end up with a number.
但是我怎么能确定这个日期是多少天前来自我的脚本呢?我想以一个数字结束。
采纳答案by marco
You can do some date arithmetics:
你可以做一些日期算术:
DATE=01/02/2010
echo $(( ( $(date +%s) - $(date -d "$DATE" +%s) ) /(24 * 60 * 60 ) ))
回答by sarnold
Convert your date and now into seconds since the epoch, subtract, divide by the number of seconds in a day:
将您的日期和现在转换为自纪元以来的秒数,减去,除以一天中的秒数:
#!/bin/bash
((a = `date -d "Wed Jan 12 02:33:22 PST 2011" +%s`))
((b = `date +%s`))
echo $(( (b-a) / (60*60*24)))
回答by Andreas WP
Use date itself as date value for date. Example 5 days ago:
使用日期本身作为日期的日期值。5天前的例子:
date -d "`date`-5days"