Laravel Eloquent - 检查返回的对象是否有效
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Laravel Eloquent - checking if returned object is valid or not
提问by StackOverflowed
I'm retrieving objects using Laravel's Eloquent, and I'm trying to see if the object is valid or not.
我正在使用 Laravel 的 Eloquent 检索对象，并试图查看该对象是否有效。
For instance
例如
$user = User->where('first_name', 'Adam')->first(); // what if there are no Adams?
$user = User->where('first_name', 'Adam')->first(); // what if there are no Adams?
I get a Builder object when there are no Adams and a User object when there is. Without using instanceof, is there a way to find out if the object returned is a valid User? Ideally, Eloquent would have just returned a null or some InvalidObject object as a response.
当没有 Adams 时我得到一个 Builder 对象，当有一个 User 对象时。不使用instanceof，有没有办法确定返回的对象是否是有效用户？理想情况下，Eloquent 会返回一个 null 或一些 InvalidObject 对象作为响应。
回答by Razor
回答by Mark Baker
If there are no matches for your query, then $user should be a falsey value
如果您的查询没有匹配项，则 $user 应该是一个 falsey 值
if (!$user) {
App::abort(404, 'User record does not exist');
}
回答by Rashi Goyal
This worked for me hope it help others I tried this and it worked for me
这对我有用希望它可以帮助其他人我尝试过这个并且对我有用
$model = Leadset::where('name',$data['name'])->first();
if(!$model) echo "no name found";
