java 如何阅读yaml中的列表？

how to read lists in yaml?

提问by PLO

I am trying to read inputs from a yaml file, having the following content:

我正在尝试从 yaml 文件中读取输入，其内容如下：

- !com.example.Contact
  name: Nathan Sweet
  age: 28
  address: pak
  phoneNumbers:
    - !com.example.Phone
      name: Home
      number: 1122
    - !com.example.Phone
      name: Work
      number: 3322
- !com.example.Contact
  name: Nathan Sw1eet
  age: 281
  address: pak1
  phoneNumbers:
    - !com.example.Phone
      name: Home1
      number: 11221
    - !com.example.Phone
      name: Work1
      number: 33211

I have the following defined:

我有以下定义：

import java.util.List;
import java.util.Map;

public class Contact 
{
    public String name;
    public int age;
    public String address;
    public List phoneNumbers;
}
public class Phone
{
    public String name;
    public String number;
}

Can some tell me the way to read these phone numbers

有人能告诉我如何读取这些电话号码吗

回答by qwerty

I had to rewrite your yaml a bit ...

我不得不稍微重写你的 yaml ......

- !!com.example.Contact
  name: Nathan Sweet
  age: 28
  address: pak
  phoneNumbers:
    - !!com.example.Phone
      name: Home
      number: 1122
    - !!com.example.Phone
      name: Work
      number: 3322
- !!com.example.Contact
  name: Nathan Sw1eet
  age: 281
  address: pak1
  phoneNumbers:
    - !!com.example.Phone
      name: Home1
      number: 11221
    - !!com.example.Phone
      name: Work1
      number: 33211

Java ...

爪哇...

package com.example;

import org.springframework.core.io.DefaultResourceLoader;
import org.springframework.core.io.Resource;
import org.yaml.snakeyaml.Yaml;
import org.yaml.snakeyaml.constructor.Constructor;

import java.io.File;
import java.io.FileInputStream;
import java.io.IOException;
import java.io.InputStream;
import java.util.Collection;

public class LoadContacts {
    private static String yamlLocation="classpath:contacts.yaml";

    public static void main(String[] args) throws IOException{
        Yaml yaml = new Yaml(new Constructor(Collection.class));
        InputStream in = null;
        Collection<Contact> contacts;
        try {
            in = new FileInputStream(new File(yamlLocation));
            contacts = (Collection<Contact>) yaml.load(in);
        } catch (IOException e) {
                final DefaultResourceLoader loader = new DefaultResourceLoader();
                final Resource resource = loader.getResource(yamlLocation);
                in = resource.getInputStream();
                contacts = (Collection<Contact>) yaml.load(in);
        } finally {
            if (in != null) {
                try {
                    in.close();
                } catch (Exception e) {
                    // no-op
                }
            }
        }
        for(Contact contact:contacts){
            System.out.println(contact.name + ":" + contact.address + ":" + contact.age );
        }
    }
}

回答by sbridges

Have you tried SnakeYaml

你试过SnakeYaml

回答by Neo

Since I came across this post to read a list of User objects, here is what I did using Hymanson

由于我遇到这篇文章是为了阅读用户对象列表，因此我使用的是 Hymanson

import com.fasterxml.Hymanson.core.type.TypeReference;
import com.fasterxml.Hymanson.databind.ObjectMapper;
import com.fasterxml.Hymanson.dataformat.yaml.YAMLFactory;

import java.io.File;
import java.io.IOException;
import java.util.List;

public class LoadContacts {

  private static String yamlLocation = "path_to/../contacts.yml";

  public static void main(String[] args) throws IOException {
    ObjectMapper mapper = new ObjectMapper(new YAMLFactory());

    try {
      List<Contact> contactList = mapper.readValue(new File(yamlLocation), new TypeReference<List<Contact>>(){});
      contactList.forEach(System.out::println);
    } catch (Exception e) {
      e.printStackTrace();
    }
  }
}

mapper.readValue(..)takes in multiple arguments such as URL, String for the first param. This solution uses File. One change I did for the OP problem to work correctly was to define phoneNumbers as follows:

mapper.readValue(..)接受多个参数，例如 URL，第一个参数的字符串。此解决方案使用File. 我为使 OP 问题正常工作所做的一项更改是将 phoneNumbers 定义如下：

   public List<Phone> phoneNumbers;