php 检查两个数组是否具有相同的值
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Check if two arrays have the same values
提问by Anna K.
[2,5,3]
[5,2,3]
They are equal because they have the same values, but not in the same order. Can I find out that without using a foreach loop with in_array() ? I dont think it would be efficient.
它们相等是因为它们具有相同的值，但顺序不同。我可以找出不使用 in_array() 的 foreach 循环吗？我不认为这会很有效率。
回答by user1844933
sort($a);
sort($b);
if ($a==$b) {//equal}
回答by TwiNight
This is a bit late to the party but in hopes that it will be useful:
这对聚会来说有点晚了，但希望它有用：
If you are sure the arrays both only contain strings or both only contain integers, then array_count_values($a) == array_count_values($b)has better time complexity. However, user1844933's answer is more general.
如果您确定数组都只包含字符串或都只包含整数，则array_count_values($a) == array_count_values($b)具有更好的时间复杂度。但是，user1844933 的回答更笼统。
回答by Conor Mancone
Coming to this party late. I had the same question but didn't want to sort, which was the immediate answer I knew would work. I came up with this simple one-liner which only works for arrays of unique values:
来晚了。我有同样的问题，但不想排序，这是我知道会起作用的直接答案。我想出了这个简单的单行代码，它只适用于唯一值数组：
$same = ( count( $a ) == count( $b ) && !array_diff( $a, $b ) )
It's also about a factor of 5 faster than the sort option. Not that either is especially slow, so I would say it is more about your personal preferences and which one you think is more clear. Personally I would rather not sort.
它也比排序选项快 5 倍。并不是说两者都特别慢，所以我会说这更多是关于您的个人喜好以及您认为哪个更清楚。我个人宁愿不排序。
Edit: Thanks Ray for pointing out the fact that this only works with arrays with unique values.
编辑：感谢 Ray 指出这仅适用于具有唯一值的数组的事实。
回答by whitebrow
If you don't want to sort arrays but just want to check equality regardless of value order use http://php.net/manual/en/function.array-intersect.phplike so:
如果您不想对数组进行排序，而只想检查相等性而不考虑值顺序，请使用http://php.net/manual/en/function.array-intersect.php像这样：
$array1 = array(2,5,3);
$array2 = array(5,2,3);
if($array1 === array_intersect($array1, $array2) && $array2 === array_intersect($array2, $array1)) {
echo 'Equal';
} else {
echo 'Not equal';
}
回答by Tamim
The best way will be using array_diffhttp://php.net/manual/en/function.array-diff.php
最好的方法是使用array_diffhttp://php.net/manual/en/function.array-diff.php
$arr1 = [2,5,3];
$arr2 = [5,2,3];
$isEqual = array_diff($arr1,$arr2) === array_diff($arr2,$arr1);
回答by seyfahni
As none of the given answers that are completely key-independent work with duplicated values (like [1,1,2]equals [1,2,2]) I've written my own.
由于给定的答案中没有一个是完全独立于键的具有重复值的工作（例如[1,1,2]equals [1,2,2]），因此我自己编写了。
This variant does not work with multi-dimensional arrays. It does check whether two arrays contain the exactly same values, regardless of their keys and order without modifying any of the arguments.
此变体不适用于多维数组。它会检查两个数组是否包含完全相同的值，而不管它们的键和顺序如何，而不修改任何参数。
function array_equals(array $either, array $other) : bool {
$copy = $either;
foreach ($other as $element) {
$key = array_search($element, $copy, true);
if ($key === false) {
return false;
}
unset($copy[$key]);
}
return empty($copy);
}
Although the question asked about a foreach-free variant, I couldn't find any solution that satisfied my requirements without a loop. Additionally most of the otherwise used functions use a loop internally too.
尽管该问题询问了 foreach-free 变体，但我找不到任何满足我要求的解决方案，而无需循环。此外，大多数其他使用的函数也在内部使用循环。
回答by jishnu
Say, if you have two arrays defined like this:
说，如果你有两个这样定义的数组：
$array1 = array(2,5,3);
$array2 = array(5,2,3);
Then you can use this piece of code to judge whether they equal:
那么就可以用这段代码来判断它们是否相等：
if(array_diff($array1,$array2) === array_diff($array2,$array1) &&count($array1)==count($array2))
{
echo 'Equal';
}
else
{
echo 'Not equal';
}
回答by IdiakosE Sunday
I came across this problem and solve it thus: I needed to ensure that two objects had the same fields So
我遇到了这个问题并因此解决了它：我需要确保两个对象具有相同的字段所以
const expectedFields = ['auth', 'message'];
const receivedFields = Object.keys(data);
const everyItemexists = expectedFields.map(i => receivedFields.indexOf(i) > -1);
const condition = everyItemexists.reduce((accumulator, item) => item && accumulator, true);
Basically, go through one of the arrays, here (I'm assuming there are of the same size though). Then check if its exists in the other array. Then i reduce the result of that.
基本上，在这里遍历其中一个数组（我假设它们的大小相同）。然后检查它是否存在于另一个数组中。然后我减少了结果。
回答by Rubin Porwal
$array1 = array(2,5,3);
$array2 = array(5,2,3);
$result = array_diff($array1, $array2);
if(empty($result))
{
echo "Both arrays are equal.";
}
else
{
echo "Both arrays are different.";
}
