java 查找全局模式匹配
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Find global pattern matches
提问by user2917629
I have a pattern like this:
我有一个这样的模式：
String pattern = "(media:\s\d+)"
I want to match a substring variation of
我想匹配的子串变体
"media:" + space/no space + X
...where Xis a set of numbers. The pattern can appear anywhere in text and followed by anything.
...其中X是一组数字。模式可以出现在文本中的任何地方，后面可以跟着任何东西。
Here's the example:
这是示例：
"The Moment of Impact text: Camera captures the deadly explosions and chaos near the marathon's finish line.media: 18962980Video shows runner ... falling as a result of the blast media: 18967421A bystander films the chaos of people positioned in between the two explosions."
“撞击瞬间文本：相机捕捉到马拉松终点线附近致命的爆炸和混乱。媒体：18962980视频显示跑步者……因爆炸而摔倒媒体：18967421旁观者拍摄了位于马拉松终点线附近的人们的混乱两次爆炸。”
For this my pattern returns only the first occurrence instead of all. Here is the code I'm using:
为此，我的模式只返回第一次出现而不是全部。这是我正在使用的代码：
String pattern = "(media:\s\d+)";
Pattern media = Pattern.compile(pattern,Pattern.MULTILINE);
java.util.regex.Matcher m = media.matcher(text);
if(m.find()) {
logger.info("-- group:"+m.group());
}
回答by Makoto
This is a case of replacing the ifwith a while. So long as the matcher isn't reset, Matcher#findwill continue to match tokens until it exhausts the string.
这是更换的情况下if用while。只要匹配器没有重置，Matcher#find就会继续匹配令牌，直到用完字符串。
You will also need to adjust the regex since you may or may not match spaces. Use the expression \\s?, which either does or does not match a single space.
您还需要调整正则表达式，因为您可能匹配也可能不匹配空格。使用表达式\\s?，它匹配或不匹配单个空格。
As a general tip, Pattern.MULTILINEonly makes sense with anchors (^and $), and since you don't have any, you can safely remove it. It's not doing any damage as is, but it will actively make your code less readable.
作为一般提示，Pattern.MULTILINE仅对锚点 (^和$)有意义，并且由于您没有锚点，因此可以安全地将其删除。它不会造成任何损害，但它会主动降低您的代码的可读性。
String pattern = "media:\s?\d+";
Pattern media = Pattern.compile(pattern);
java.util.regex.Matcher m = media.matcher(text);
while(m.find()) {
logger.info("-- group:"+m.group());
}
回答by james jelo4kul
The reason why it didn't repeat or loop is because you didn't use a while statement. For it to work, change your if statement to while.
它没有重复或循环的原因是因为您没有使用 while 语句。要使其正常工作，请将您的 if 语句更改为 while。
while(m.find()) {
logger.info("-- group:"+m.group());
}
Use this modification to your regex pattern:
将此修改用于您的正则表达式模式：
String pattern = "(media:\s?\d+)"
The reason for the change ie \\s?is to enable you match the pattern even if there is no space there. Hope this helps!
更改 ie 的原因\\s?是使您能够匹配模式，即使那里没有空间。希望这可以帮助！
