连续运行 bash 脚本
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continuously run a bash script
提问by David Vasandani
{ while IFS=';' read u1 p1 u2 p2; do
imapsync/imapsync --usecache --host1 secure.emailsrvr.com --user1 "$u1" --password1 "$p1" \
--host2 imap.gmail.com --ssl2 --user2 "$u2" --password2 "$p2" ...
done ; } < users1-33.txt
How can I continuously run this script so that when it completes it just starts over again?
我怎样才能连续运行这个脚本，以便在它完成时重新开始？
回答by kojiro
Many UNIXy systems have a tool called watchthat will repeatedly execute a command (by default every 2 seconds). While watchis not a standard POSIX tool, if you have or can install it it is a very simple way to achieve essentially what you're asking for. Put your code in a file and watchit thus:
许多 UNIXy 系统都有一个称为watch重复执行命令的工具（默认情况下每 2 秒执行一次）。虽然watch它不是标准的 POSIX 工具，但如果您拥有或可以安装它，它是一种非常简单的方法，可以基本上实现您的要求。将您的代码放在一个文件中，然后观察它：
watch bash -c your_script
回答by Brian Cain
Try wrapping it in a function and iterating over it.
尝试将其包装在一个函数中并对其进行迭代。
function go()
{
{ while IFS=';' read u1 p1 u2 p2; do
imapsync/imapsync --usecache --host1 secure.emailsrvr.com --user1 "$u1" --password1 "$p1" \
--host2 imap.gmail.com --ssl2 --user2 "$u2" --password2 "$p2" ...
done ; } < users1-33.txt
}
while true
do
go
done
Or you can reference go()from another file:
或者您可以go()从另一个文件中引用：
#!/bin/sh
. /the/original/source_file.sh
go
回答by matchew
have you considered putting the script in your crontab to run every minute?
你有没有考虑把脚本放在你的 crontab 中每分钟运行一次？
so on a debian based system. (ubuntu)
所以在基于 debian 的系统上。(Ubuntu)
crontab -e
crontab -e
# m h dom mon dow command
*/1 * * * * /usr/local/bin/scriptToRun.sh
would have the script run every minute
会让脚本每分钟运行一次
