Ruby-on-rails 我需要为我的 rails 应用程序生成 uuid。我有哪些选择（宝石）？
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I need to generate uuid for my rails application. What are the options(gems) I have?
提问by Virtual
I use Rails 3.0.20 and ruby 1.8.7 (2011-06-30 patchlevel 352)
我使用 Rails 3.0.20 和 ruby 1.8.7 (2011-06-30 patchlevel 352)
Please suggest me the best plugin to generate guid.
请建议我最好的插件来生成 guid。
回答by apneadiving
回答by Hasan Iqbal
The first thing I would suggest is that please upgrade your ruby and rails version.
我建议的第一件事是请升级您的 ruby 和 rails 版本。
A very good way of generating guid is SecureRandom, which is a ruby module. With easy usage.
生成 guid 的一个很好的方法是SecureRandom，它是一个 ruby 模块。使用方便。
require 'securerandom'
guid = SecureRandom.hex(10) #or whatever value you want instead of 10
回答by riley
I would suggest using PostgreSQL and using the uuid column built in, it autogenerates UUID based on type you create the column.
我建议使用 PostgreSQL 并使用内置的 uuid 列，它会根据您创建列的类型自动生成 UUID。
Example in Rails 3 migration
Rails 3 迁移示例
execute <<-SQL
CREATE TABLE some_items (id uuid PRIMARY KEY DEFAULT uuid_generate_v1());
SQL
execute <<-SQL
CREATE TABLE some_items (id uuid PRIMARY KEY DEFAULT uuid_generate_v1());
SQL
Might be a better way to do this in Rails 4.
可能是在 Rails 4 中执行此操作的更好方法。
回答by Rameshwar Vyevhare
Please see in detail, how to use securerandom ruby standard library to use UUID with example in rails 3.X and 4.X
请详细查看如何使用securerandom ruby标准库在rails 3.X和4.X中以示例使用UUID
create usesguid.rb file in your lib/usesguid.rb and paste below code in that -
在你的 lib/usesguid.rb 中创建 usesguid.rb 文件并粘贴下面的代码 -
require 'securerandom'
module ActiveRecord
module Usesguid #:nodoc:
def self.append_features(base)
super
base.extend(ClassMethods)
end
module ClassMethods
def usesguid(options = {})
class_eval do
self.primary_key = options[:column] if options[:column]
after_initialize :create_id
def create_id
self.id ||= SecureRandom.uuid
end
end
end
end
end
end
ActiveRecord::Base.class_eval do
include ActiveRecord::Usesguid
end
add following line in your config/application.rb to load file -
在 config/application.rb 中添加以下行以加载文件 -
require File.dirname(__FILE__) + '/../lib/usesguid'
Create migration script for UUID function as mentioned below to -
为 UUID 函数创建迁移脚本，如下所述 -
class CreateUuidFunction < ActiveRecord::Migration
def self.up
execute "create or replace function uuid() returns uuid as 'uuid-ossp', 'uuid_generate_v1' volatile strict language C;"
end
def self.down
execute "drop function uuid();"
end
end
Here is example for contact migration, how we can use it -
这是联系人迁移的示例，我们如何使用它 -
class CreateContacts < ActiveRecord::Migration
def change
create_table :contacts, id: false do |t|
t.column :id, :uuid, null:false
t.string :name
t.string :mobile_no
t.timestamps
end
end
end
Final how to use into your model
最终如何在您的模型中使用
class Contact < ActiveRecord::Base
usesguid
end
This will help you to configure UUID for your rails application.
这将帮助您为 Rails 应用程序配置 UUID。
This can be useful for Rails 3.0, 3.1, 3.2 and 4.0 as well.
这对 Rails 3.0、3.1、3.2 和 4.0 也很有用。
Please let me know If you have any issue while using it, so simple!
如果您在使用它时遇到任何问题，请告诉我，就这么简单！
Other options for Rails4 here
Rails4 的其他选项在这里
