使用 PHP 获取 img src
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Get img src with PHP
提问by pangi
I would like to get the SRC attribute into a variable in this example:
在此示例中，我想将 SRC 属性放入一个变量中：
<img border="0" src="/images/image.jpg" alt="Image" width="100" height="100" />
So for example - I would like to get a variable $foo = "/images/image.jpg".
Important! The src attribute will be dynamic, so it mustn't be hardcoded.
Is there any quick and easy way to do this?
例如 - 我想得到一个变量$foo = "/images/image.jpg"。重要的！src 属性将是动态的，所以它不能被硬编码。有什么快速简便的方法可以做到这一点？
Thanks!
谢谢！
EDIT: The image will be a part of a huge string that is basically the content of a news story. So the image is just a part of that.
编辑：图像将是一个巨大的字符串的一部分，基本上是新闻故事的内容。所以图像只是其中的一部分。
EDIT2: There will be more images in this string, and I would only want to get the src of the first one. Is this possible?
EDIT2：此字符串中会有更多图像，我只想获取第一个图像的 src。这可能吗？
回答by hakre
Use a HTML parser like DOMDocumentand then evaluate the value you're looking for with DOMXpath:
使用 HTML 解析器DOMDocument，然后使用以下方法评估您要查找的值DOMXpath：
$html = '<img id="12" border="0" src="/images/image.jpg"
alt="Image" width="100" height="100" />';
$doc = new DOMDocument();
$doc->loadHTML($html);
$xpath = new DOMXPath($doc);
$src = $xpath->evaluate("string(//img/@src)"); # "/images/image.jpg"
Or for those who really need to save space:
或者对于那些真正需要节省空间的人：
$xpath = new DOMXPath(@DOMDocument::loadHTML($html));
$src = $xpath->evaluate("string(//img/@src)");
And for the one-liners out there:
对于那里的单线：
$src = (string) reset(simplexml_import_dom(DOMDocument::loadHTML($html))->xpath("//img/@src"));
回答by anubhava
You would be better off using a DOM parser for this kind of HTML parsing. Consider this code:
您最好使用 DOM 解析器进行这种 HTML 解析。考虑这个代码：
$html = '<img id="12" border="0" src="/images/image.jpg"
alt="Image" width="100" height="100" />';
$doc = new DOMDocument();
libxml_use_internal_errors(true);
$doc->loadHTML($html); // loads your html
$xpath = new DOMXPath($doc);
$nodelist = $xpath->query("//img"); // find your image
$node = $nodelist->item(0); // gets the 1st image
$value = $node->attributes->getNamedItem('src')->nodeValue;
echo "src=$value\n"; // prints src of image
OUTPUT:
输出：
src=/images/image.jpg
回答by Torsten
I have done that the more simple way, not as clean as it should be but it was a quick hack
我用更简单的方法做到了这一点，不像它应该的那样干净，但它是一个快速的黑客
$htmlContent = file_get_contents('pageURL');
// read all image tags into an array
preg_match_all('/<img[^>]+>/i',$htmlContent, $imgTags);
for ($i = 0; $i < count($imgTags[0]); $i++) {
// get the source string
preg_match('/src="([^"]+)/i',$imgTags[0][$i], $imgage);
// remove opening 'src=' tag, can`t get the regex right
$origImageSrc[] = str_ireplace( 'src="', '', $imgage[0]);
}
// will output all your img src's within the html string
print_r($origImageSrc);
回答by kba
I know people say you shouldn't use regular expressions to parse HTML, but in this case I find it perfectly fine.
我知道人们说你不应该使用正则表达式来解析 HTML，但在这种情况下，我发现它非常好。
$string = '<img border="0" src="/images/image.jpg" alt="Image" width="100" height="100" />';
preg_match('/<img(.*)src(.*)=(.*)"(.*)"/U', $string, $result);
$foo = array_pop($result);
回答by CONvid19
$imgTag = <<< LOB
<img border="0" src="/images/image.jpg" alt="Image" width="100" height="100" />
<img border="0" src="/images/not_match_image.jpg" alt="Image" width="100" height="100" />
LOB;
preg_match('%<img.*?src=["\'](.*?)["\'].*?/>%i', $imgTag, $matches);
$imgSrc = $matches[1];
NOTE:You should use an HTML Parser like DOMDocumentand NOTa regex.
注意：您应该使用 HTML 解析器，DOMDocument而不是正则表达式。
回答by squarephoenix
$str = '<img border="0" src=\'/images/image.jpg\' alt="Image" width="100" height="100"/>';
preg_match('/(src=["\'](.*?)["\'])/', $str, $match); //find src="X" or src='X'
$split = preg_split('/["\']/', $match[0]); // split by quotes
$src = $split[1]; // X between quotes
echo $src;
Other regexp's can be used to determine if the pulled src tag is a picture like so:
其他正则表达式可用于确定拉取的 src 标签是否是这样的图片：
if(preg_match('/([jpg]{3}$)|([gif]{3}$)|([jpeg]{3}$)|([bmp]{3}$)|([png]{3}$)/', $src) == 1) {
//its an image
}
回答by Jitendra
There could be two easy solutions:
可能有两个简单的解决方案：
- HTML it self is an xml so you can use any XML parsing method if u load the tag as XML and get its attribute tottally dynamically even dom data attribute (like data-time or anything).....
- Use any html parser for php like http://mbe.ro/2009/06/21/php-html-to-array-working-one/or php parse html to array Google this
- HTML本身就是一个xml，因此如果您将标签加载为XML并完全动态地获取其属性甚至dom数据属性（如数据时间或任何东西），则您可以使用任何XML解析方法......
- 对 php 使用任何 html 解析器，如 http://mbe.ro/2009/06/21/php-html-to-array-working-one/或 php 解析 html 来排列谷歌这个
