在 Java 中查询 XML 的最简单方法
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Simplest way to query XML in Java
提问by
I have small Strings with XML, like:
我有带有 XML 的小字符串，例如：
String myxml = "<resp><status>good</status><msg>hi</msg></resp>";
which I want to query to get their content.
我想查询以获取其内容。
What would be the simplest way to do this?
什么是最简单的方法来做到这一点？
回答by Pierre
convert this string into a DOM object and visit the nodes:
将此字符串转换为 DOM 对象并访问节点：
Document dom= DocumentBuilderFactory().newDocumentBuilder().parse(new InputSource(new StringReader(myxml)));
Element root= dom.getDocumentElement();
for(Node n=root.getFirstChild();n!=null;n=n.getNextSibling())
{
System.err.prinlnt("Current node is:"+n);
}
回答by McDowell
XPathusing Java 1.5 and above, without external dependencies:
XPath使用 Java 1.5 及更高版本，没有外部依赖：
String xml = "<resp><status>good</status><msg>hi</msg></resp>";
XPathFactory xpathFactory = XPathFactory.newInstance();
XPath xpath = xpathFactory.newXPath();
InputSource source = new InputSource(new StringReader(xml));
String status = xpath.evaluate("/resp/status", source);
System.out.println("satus=" + status);
回答by JavaRocky
After your done with simple ways to query XML in java. Look at XOM.
在你完成了在 java 中查询 XML 的简单方法之后。看看 XOM。
回答by Jonik
Using dom4j, similar to McDowell's solution:
使用dom4j，类似于McDowell 的解决方案：
String myxml = "<resp><status>good</status><msg>hi</msg></resp>";
Document document = new SAXReader().read(new StringReader(myxml));
String status = document.valueOf("/resp/msg");
System.out.println("status = " + status);
XML handling is a bit simpler using dom4j. And several other comparable XML libraries exist. Alternatives to dom4j are discussed here.
回答by Peter ?tibrany
Here is example of how to do that with XOM:
以下是如何使用XOM执行此操作的示例：
String myxml = "<resp><status>good</status><msg>hi</msg></resp>";
Document document = new Builder().build(myxml, "test.xml");
Nodes nodes = document.query("/resp/status");
System.out.println(nodes.get(0).getValue());
I like XOM more than dom4j for its simplicity and correctness. XOM won't let you create invalid XML even if you want to ;-) (e.g. with illegal characters in character data)
我喜欢 XOM 多于 dom4j，因为它的简单性和正确性。即使您想要，XOM 也不会让您创建无效的 XML ;-)（例如在字符数据中使用非法字符）
回答by OscarRyz
@The comments of this answer:
@这个答案的评论 ：
You can create a method to make it look simpler
你可以创建一个方法让它看起来更简单
String xml = "<resp><status>good</status><msg>hi</msg></resp>";
System.out.printf("satus= %s\n", getValue("/resp/status", xml ) );
The implementation:
实施：
public String getValue( String path, String xml ) {
return XPathFactory
.newInstance()
.newXPath()
.evaluate( path , new InputSource(
new StringReader(xml)));
}
回答by vtd-xml-author
Here is a code snippet of querying your XML with VTD-XML
这是使用VTD-XML查询 XML 的代码片段
import com.ximpleware.*;
public class simpleQuery {
public static void main(String[] s) throws Exception{
String myXML="<resp><status>good</status><msg>hi</msg></resp>";
VTDGen vg = new VTDGen();
vg.setDoc(myXML.getBytes());
vg.parse(false);
VTDNav vn = vg.getNav();
AutoPilot ap = new AutoPilot(vn);
ap.selectXPath("/resp/status");
int i = ap.evalXPath();
if (i!=-1)
System.out.println(" result ==>"+vn.toString(i));
}
}
