windows sed：如何用“\r”“\n”替换 CR 和/或 LF，因此任何文件都将在一行中
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sed: how to replace CR and/or LF with "\r" "\n", so any file will be in one line
提问by 999
I have files like
我有类似的文件
aaa
bbb
ccc
啊啊啊
bbb
抄送
I need them to sed into aaa\r\nbbb\r\nccc
我需要他们加入 aaa\r\nbbb\r\nccc
It should work either for unix and windows replacing them with \ror \r\naccordingly
它应该适用于 unix 和 windows 替换它们\r或\r\n相应地
The problem is that sedadds \nat the end of line but keeps lines separated. How can I fix it?
问题是在行尾sed添加\n但保持行分隔。我该如何解决？
回答by bdk
These two commands together should do what you want:
这两个命令一起应该做你想要的：
sed ':a;N;$!ba;s/\r/\r/g'
sed ':a;N;$!ba;s/\n/\n/g'
Pass your input file through both to get the output you want. Theres probably a way to combine them into a single expression.
通过两者传递您的输入文件以获得您想要的输出。可能有一种方法可以将它们组合成一个表达式。
Stolen and Modified from this question:
从这个问题被盗和修改：
回答by bobbogo
tr -s '\r' '\n' <file | unix2dos
EDIT(it's been pointed out that the above misses the point entirely! ?///?)
编辑（有人指出上述内容完全没有抓住重点！？///？）
tr -s '\r' '\n' <file | perl -pe 's/\s+$/\r\n/'
The trgets rid of empty lines and dos line endings. The pipe means two processes—good on modern hardware.
该tr出手的空行和DOS行结束。管道意味着两个进程——在现代硬件上很好。
回答by zwol
It's possible to merge lines in sed, but personally, I consider needing to change line breaks a sign that it's time to give up on sed and use a more powerful language instead. What you want is one line of perl:
可以在 sed 中合并行，但就个人而言，我认为需要更改换行符表明是时候放弃 sed 并改用更强大的语言了。你想要的是一行 perl：
perl -e 'undef $/; while (<>) { s/\n/\n/g; s/\r/\r/g; print $_, "\n" }'
or 12 lines of python:
或 12 行 python：
#! /usr/bin/python
import fileinput
from sys import stdout
first = True
for line in fileinput.input(mode="rb"):
if fileinput.isfirstline() and not first:
stdout.write("\n")
if line.endswith("\r\n"): stdout.write(line[:-2] + "\r\n")
elif line.endswith("\n"): stdout.write(line[:-1] + "\n")
elif line.endswith("\r"): stdout.write(line[:-1] + "\r")
first = False
if not first: stdout.write("\n")
or 10 lines of C to do the job, but then a whole bunch more because you have to process argvyourself:
或者 10 行 C 来完成这项工作，但是还有一大堆，因为你必须argv自己处理：
#include <stdio.h>
void process_one(FILE *fp)
{
int c;
while ((c = getc(fp)) != EOF)
if (c == '\n') fputs("\n", stdout);
else if (c == '\r') fputs("\r", stdout);
else putchar(c);
fclose(fp);
putchar('\n');
}
int main(int argc, char **argv)
{
FILE *cur;
int i, consumed_stdin = 0, rv = 0;
if (argc == 1) /* no arguments */
{
process_one(stdin);
return 0;
}
for (i = 1; i < argc; i++)
{
if (argc[i][0] == '-' && argc[i][1] == 0)
{
if (consumed_stdin)
{
fputs("cannot read stdin twice\n", stderr);
rv = 1;
continue;
}
cur = stdin;
consumed_stdin = 1;
}
else
{
cur = fopen(ac[i], "rb");
if (!cur)
{
perror(ac[i]);
rv = 1;
continue;
}
}
process_one(cur);
}
return rv;
}
回答by glenn Hymanman
awk '{printf("%s\\r\\n",$0)} END {print ""}' file
awk '{printf("%s\\r\\n",$0)} END {print ""}' file
