获取数组中除了第一个元素之外的所有元素..？(PHP)
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Get all elements in array besides the first one.. ? (php)
提问by Roeland
Is there a way to specify getting all but the first element in an array? I generally use foreach() to loop through my arrays.
有没有办法指定获取数组中除第一个元素之外的所有元素？我通常使用 foreach() 来循环遍历我的数组。
say array(1,2,3,4,5), i would only want 2, 3, 4 ,5 to show and for it to skip 1.
说数组（1,2,3,4,5），我只想显示 2, 3, 4 ,5 并让它跳过 1。
回答by micahwittman
$arr = array(1,2,3,4,5);
$all_but_the_first_element_array = array_slice($arr, 1);
回答by Andrew Moore
There are multiple ways of approaching this problem.
有多种方法可以解决这个问题。
The first solution is to use a flag boolean to indicate the first element and proceed in your foreach
第一个解决方案是使用标志布尔值来指示第一个元素并在您的 foreach
$firstElement = true;
foreach($array as $key => $val) {
if($firstElement) {
$firstElement = false;
} else {
echo "$key => $val\n";
}
}
If your elements are naturally numerically indexed, you do not need the boolean flag, you can simply check if the key is 0.
如果您的元素是自然数字索引的，则不需要布尔标志，您可以简单地检查键是否为 0。
foreach($array as $key => $val) {
if($key === 0) continue;
echo "$key => $val\n";
}
The second way is to cheat your way into a naturally numerically indexed array if it isn't already. I will use array_keys()to get a naturally numerically indexed array of keys and loop it.
第二种方法是欺骗你进入一个自然数字索引的数组，如果它还没有的话。我将array_keys()用来获取一个自然数字索引的键数组并循环它。
$keys = array_keys($array);
foreach($keys as $index => $key) {
if($index === 0) continue;
$val = $array[$key];
echo "$key => $val\n";
}
The third way is to use the array internal pointer to skip the first element and then continue in a loop by using reset(), next(), list(), and each(). Performance and resource-wise, this is the best option. Maintainability suffers greatly though.
第三种方式是通过使用使用数组内部指针以跳过所述第一元件，然后继续在一个循环中reset()，next()，list()，和each()。在性能和资源方面，这是最好的选择。但是可维护性受到很大影响。
reset($array); // Reset pointer to 0
next($array); // Advance pointer to 1
while (list($key, $val) = each($array)) {
echo "$key => $val\n";
}
If you don't mind losing the first element of the array, you can array_shift()it.
如果您不介意丢失数组的第一个元素，则可以array_shift()。
array_shift($array);
foreach($array as $key => $val) {
echo "$key => $val\n";
}
You can also array_slice()the array. I'm also using count()in order to be able to set the preserve_keysparameter to true.
你也可以array_slice()数组。我也在使用count()以便能够将preserve_keys参数设置为true.
$sliced = array_slice($array, 1, count($array)-1, true);
foreach($sliced as $key => $val) {
echo "$key => $val\n";
}
回答by santosc
array_shift()
数组移位（）
http://us2.php.net/manual/en/function.array-shift.php
http://us2.php.net/manual/en/function.array-shift.php
example used in the site:
网站中使用的示例：
<?php
$stack = array("orange", "banana", "apple", "raspberry");
$fruit = array_shift($stack);
print_r($stack);
?>
The above example will output:
上面的例子将输出：
Array
(
[0] => banana
[1] => apple
[2] => raspberry
)
**remember that the pointer to the array is reset (new value) after the shift
**记住在移位后指向数组的指针被重置（新值）
回答by Sarfraz
Well, there can be many ways for that as we have great deal of array-manipulation functions available. However i use the following method for that:
好吧，因为我们有大量可用的数组操作函数，所以可以有很多方法。但是我使用以下方法：
$orig_array = array(1, 2, 3, 4 ,5);
array_shift($orig_array);
print_r($orig_array);
