java.text.ParseException：无法解析的日期：“2014-06-04”（偏移量 5）
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java.text.ParseException: Unparseable date: "2014-06-04" (at offset 5)
提问by Anchit Mittal
I want to parse the date into a desired format but i am receiving an exception every time. i know it is easy to implement but i am facing some problem don't know where exactly.:
我想将日期解析为所需的格式，但每次都收到异常。我知道这很容易实现，但我面临一些不知道具体在哪里的问题：
Exception: java.text.ParseException: Unparseable date: "2014-06-04" (at offset 5)
Following is my code:
以下是我的代码：
private String getconvertdate(String date) {
DateFormat inputFormat = new SimpleDateFormat("yyyy-MMM-dd HH:mm:ss",Locale.ENGLISH);
inputFormat.setTimeZone(TimeZone.getTimeZone("UTC"));
DateFormat outputFormat = new SimpleDateFormat("dd-MMM-yyyy",Locale.ENGLISH);
Date parsed = null;
try {
parsed = inputFormat.parse(date);
} catch (ParseException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
String outputText = outputFormat.format(parsed);
return outputText;
}
Input to method: 2014-06-04
方法输入：2014-06-04
Expected Output: 06-Jun-2014
预期产出：2014 年 6 月 6 日
I have followed some Ref. from Stackoverflow.com, but still he problem persist. Please Help.
我遵循了一些参考文献。来自 Stackoverflow.com，但他的问题仍然存在。请帮忙。
采纳答案by Jens
You have no time part in your string: and the Month has only two character replace
您的字符串中没有时间部分：并且月份只有两个字符替换
new SimpleDateFormat("yyyy-MMM-dd HH:mm:ss",Locale.ENGLISH);
with
和
new SimpleDateFormat("yyyy-MM-dd",Locale.ENGLISH);
回答by Abs
Maybe you need to tackle different input formats Then catch the currently unmanaged format exception (just a sample):
也许您需要处理不同的输入格式然后捕获当前非托管格式异常（只是一个示例）：
private String getconvertdate(String date) {
System.out.println(date.length());
DateFormat inputFormat = null;
if(date.length() == 20)
inputFormat = new SimpleDateFormat("yyyy-MMM-dd HH:mm:ss",Locale.ENGLISH);
if(date.length() == 10)
inputFormat = new SimpleDateFormat("yyyy-MM-dd",Locale.ENGLISH) ;
if(null == inputFormat)
return "Format invalid";
inputFormat.setTimeZone(TimeZone.getTimeZone("UTC"));
DateFormat outputFormat = new SimpleDateFormat("dd-MMM-yyyy",Locale.ENGLISH);
Date parsed = null;
try {
parsed = inputFormat.parse(date);
} catch (ParseException e) {
return "Input Date invalid";
}
String outputText = outputFormat.format(parsed);
return outputText;
}
回答by Haresh Chhelana
// Try this way,hope this will help you to solve your problem....
public String convertDateStringFormat(String strDate, String fromFormat, String toFormat){
try{
SimpleDateFormat sdf = new SimpleDateFormat(fromFormat);
sdf.setTimeZone(TimeZone.getTimeZone("UTC"));
SimpleDateFormat dateFormat2 = new SimpleDateFormat(toFormat.trim());
return dateFormat2.format(sdf.parse(strDate));
}catch (Exception e) {
e.printStackTrace();
return "";
}
}
回答by AndroidGuy
In my case, I was using ::
就我而言，我使用的是 ::
SimpleDateFormat todaySdf = new SimpleDateFormat("dd MMM yyyy", Locale.ENGLISH);
changed it to
把它改成
SimpleDateFormat todaySdf = new SimpleDateFormat("dd MM yyyy", Locale.ENGLISH);
and it worked.. the extra M was the culprit !!
它奏效了.. 额外的 M 是罪魁祸首！
